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2 years ago

7

Tyler has learned that potential energy is energy stored. Tyler's teacher asks the students to come up with a demonstration of p

otential energy. Which of the following would best work for this demonstration?
A

A parked car in the driveway

B

Wheels spinning on the ground

C

A rock after it has been thrown

D

A child at the top of a slide

2 answers:

Advocard [28]2 years ago

7 0

D.A child at the top of a slide

MrMuchimi2 years ago

3 0

D; cause potential energy is when something has the potential to move

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A rifle, which has a mass of 5.50 kg., is used to fire a bullet, which has a massof m = 65.0 grams., at a "ballistics pendulum".

Alex787 [66]

Answer:

Part a)

$U = 13 J$

Part b)

$v = 2.28 m/s$

Part c)

$v = 177.66 m/s$

Part d)

$W = 1012.7 J$

Part e)

$v = 2.1 m/s$

Part f)

$E = 1037.2 J$

Explanation:

Part a)

As we know that the maximum angle deflected by the pendulum is

$\theta = 38^o$

so the maximum height reached by the pendulum is given as

$h = L(1 - cos\theta)$

so we will have

$h = L(1 - cos38)$

$h = 1.25(1 - cos38)$

$h = 0.265 m$

now gravitational potential energy of the pendulum is given as

$U = mgh$

$U = 5(9.81)(0.265)$

$U = 13 J$

Part b)

As we know that there is no energy loss while moving upwards after being stuck

so here we can use mechanical energy conservation law

so we have

$mgh = \frac{1}{2}mv^2$

$v = \sqrt{2gh}$

$v = \sqrt{2(9.81)(0.265)}$

$v = 2.28 m/s$

Part c)

now by momentum conservation we can say

$mv = (M + m) v_f$

$0.065 v = (5 + 0.065)2.28$

$v = 177.66 m/s$

Part d)

Work done by the bullet is equal to the change in kinetic energy of the system

so we have

$W = \frac{1}{2}mv^2 - \frac{1}{2}(m + M)v_f^2$

$W = \frac{1}{2}(0.065)(177.66)^2 - \frac{1}{2}(5 + 0.065)2.28^2$

$W = 1012.7 J$

Part e)

recoil speed of the gun can be calculated by momentum conservation

so we will have

$0 = mv_1 + Mv_2$

$0 = 0.065(177.6) + 5.50 v$

$v = 2.1 m/s$

Part f)

Total energy released in the process of shooting of gun

$E = \frac{1}{2}Mv^2 + \frac{1}{2}mv_1^2$

$E = \frac{1}{2}(5.50)(2.1^2) + \frac{1}{2}(0.065)(177.6^2)$

$E = 1037.2 J$

6 0

2 years ago

Lucille is finding it difficult to play soccer after school. Her doctor thinks that her cells might not be getting enough oxygen

Bad White [126]

Explanation:

Lucile

Lucile cells needs a huge abundance of glucose and oxygen supply in order for her body to function properly and participate in a soccer game.

Playing a soccer game is energy demanding. The body's energy supply is met by the metabolism of glucose in cells using oxygen.

The problem with Lucille's respiratory and circulatory system can make it difficult for her to take part in soccer game because the needed energy would not be available for her to participate in the game.

Respiratory system is saddled with the responsibility of bringing enough oxygen to body system through gaseous exchange and metabolism.
The circulatory system carries the oxygen to the different body cells to where they are need. It also takes the deoxygenated blood to where they can get oxygenated.
We can clearly see that if respiratory and circulatory systems are not functioning well, Lucille's cells will not be able to furnish her with the much needed energy.

Ezra

Ezra needs energy to play basketball well. The energy is produced via the glucose in the starch and the oxygen from breathing.

When starch is broken down, glucose is produced.

How it works;

The digestive, circulatory and respiratory systems are all important here. They ensure that Ezra gets the needed energy from the food he is eating. Proteins also have the capability of producing energy when there is shortage of starch in the body.

Ezra's digestive system through a couple of processes releases glucose from the food he eats especially the bread in the sandwich.

The glucose is stored in the body and made available for use when in need.

The glucose is used to produce energy.

When Ezra breathes, the circulatory system ensures gaseous exchange with the surroundings. Oxygen rich blood is taken the cells where they combine with glucose for their metabolic actions. Oxygen deficient bloods are carried away.

In the cell, a special apparatus called the mitochondria combines glucose with oxygen and energy is liberated. The energy is used by Ezra to run while playing basketball

learn more:

Cellular respiration brainly.com/question/3447259

#learnwithBrainly

7 0

2 years ago

A package is dropped from a helicopter that is descending steadily at a speed v0. After t seconds have elapsed, consider the fol

qaws [65]

Answer:

Part a)

$v = \sqrt{v_o^2 + g^2t^2}$

Part b)

$d = \frac{1}{2}gt^2$

Part c)

$v_f = v_o - gt$

Part d)

$d = \frac{1}{2}gt^2$

Explanation:

Part a)

As we know that speed of package is same as that of helicopter in horizontal direction

So after time "t" the velocity in x direction will remain constant while in Y direction it will go free fall

So we have

$v_y = -gt$

$v = \sqrt{v_x^2 + v_y^2}$

$v = \sqrt{v_o^2 + g^2t^2}$

Part b)

Distance from helicopter is same as the distance of free fall

so we will have

$d = \frac{1}{2}gt^2$

Part c)

If helicopter is rising upwards with uniform speed

then final speed of the package after time t is given as

$v_f = v_i + at$

$v_f = v_o - gt$

Part d)

distance from helicopter

$d = \frac{1}{2}gt^2$

8 0

2 years ago

Read 2 more answers

The amount of light that undergoes reflection or transmission is demonstrated by how bright the reflected or transmitted ray is.

melamori03 [73]

If you subscribe I’ll answer QF Aotrx

8 0

2 years ago

A seasoned mini golfer is trying to make par on a tricky number five hole. The golfer can complete the hole by hitting the ball

liberstina [14]

Answer:5.17 m/s

Explanation:

Given

let u be the speed at cliff initial point

range over cliff is 1.45 m

and range of projectile is given by

$R=\frac{u^2\sin 2\theta }{g}$

$1.45=\frac{u^2\sin 90}{9.8}$

u=3.77 m/s

Conserving Energy

$E_{bottom}=E_{initial\ point\ at\ cliff}$

Kinetic energy=Kinetic energy +Potential energy gained

Let v be the initial velocity

$\frac{mv^2}{2}=mgh+\frac{mu^2}{2}$

$v^2=u^2+2gh$

$v=\sqrt{u^2+2gh}$

$v=\sqrt{3.77^2+2\time 9.8\times 0.64}$

$v=\sqrt{26.75}=5.17 m/s$

5 0

1 year ago