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Otrada [13]
2 years ago
7

Tyler has learned that potential energy is energy stored. Tyler's teacher asks the students to come up with a demonstration of p

otential energy. Which of the following would best work for this demonstration?
A

A parked car in the driveway

B

Wheels spinning on the ground

C

A rock after it has been thrown

D

A child at the top of a slide
Physics
2 answers:
Advocard [28]2 years ago
7 0
D.A child at the top of a slide
MrMuchimi2 years ago
3 0
D; cause potential energy is when something has the potential to move
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You are installing a new spark plug in your car, and the manual specifies that it be tightened to a torque that has a magnitude
klemol [59]
We are given 

the torque requirement of 97 Newton meter. 

The formula of the torque is

τ = r * F * sinθ

where 

τ is the torque
r = radius from the axis of rotation to the point of application. 
F = force exerted 
θ = the angle between the lever arm and the radius

Try to substitute the given and solve for F. 
5 0
1 year ago
The image shows the electric field lines around two charged particles. 2 balls separated vertically. Lines with arrowheads run f
slava [35]

Answer:

4

Explanation:

Egenuity

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2 years ago
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How long does it take for the velocity of the rain drop to reach 99% of its terminal velocity? (assume the conditions from part
vodomira [7]
If you think about it its part a and b 
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2 years ago
Cass is walking her dog (Oreo) around the neighborhood. Upon arriving at Calina's house (a friend of Oreo's), Oreo turns part mu
MArishka [77]

Answer:

Horizontal component: F_x = 58\ N

Vertical component: F_y = 33.5\ N

Explanation:

To find the horizontal and vertical components of the force, we just need to multiply the magnitude of the force by the cosine and sine of the angle with the horizontal, respectively.

Therefore, for the horizontal component, we have:

F_x = F * cos(angle)

F_x = 67 * cos(30)

F_x = 58\ N

For the vertical component, we have:

F_y = F * sin(angle)

F_y = 67 * sin(30)

F_y = 33.5\ N

So the horizontal component of the tension force is 58 N and the vertical component is 33.5 N.

4 0
2 years ago
Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of m
OverLord2011 [107]

To solve this problem we will start from the definition of energy of a spring mass system based on the simple harmonic movement. Using the relationship of equality and balance between both systems we will find the relationship of the amplitudes in terms of angular velocities. Using the equivalent expressions of angular velocity we will find the final ratio. This is,

The energy of the system having mass m is,

E_m = \frac{1}{2} m\omega_1^2A_1^2

The energy of the system having mass 2m is,

E_{2m} = \frac{1}{2} (2m)\omega_1^2A_1^2

For the two expressions mentioned above remember that the variables mean

m = mass

\omega =Angular velocity

A = Amplitude

The energies of the two system are same then,

E_m = E_{2m}

\frac{1}{2} m\omega_1^2A_1^2=\frac{1}{2} (2m)\omega_1^2A_1^2

\frac{A_1^2}{A_2^2} = \frac{2\omega_2^2}{\omega_1^2}

Remember that

k = m\omega^2 \rightarrow \omega^2 = k/m

Replacing this value we have then

\frac{A_1}{A_2} = \sqrt{\frac{2(k/m_2)}{(k/m_1)^2}}

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{m_1}{m_1}}

But the value of the mass was previously given, then

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{m}{2m}}

\frac{A_1}{A_2} = \sqrt{2} \sqrt{\frac{1}{2}}

\frac{A_1}{A_2} = 1

Therefore the ratio of the oscillation amplitudes it is the same.

5 0
2 years ago
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