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sergeinik [125]
2 years ago
12

When you hold your hands at your sides, you may have noticed that the veins sometimes bulge--the height difference between your

heart and your hands produces increased pressure in the veins. The same thing happens in the arteries. If the average arterial pressure at your heart is a typical 100 mmHg, what is the average arterial pressure in your hands when they are held at your side? Assume your hands are 60 cm below your heart.
Physics
1 answer:
hodyreva [135]2 years ago
7 0

To solve this problem it is necessary to use the concepts related to pressure and pressure, absolute and atmospheric.

Average arterial pressure in the hands,

P = 100mmHg+ h*\rho_{blood}g

Where,

P = Pressure

h = height (at this case the length of the arm)

Replacing with our values

P = 100mm(Hg)+(600mm)(\frac{\rho_{blood}}{\rho_{mercury}})(Hg)

P = 100mmHg+600*\frac{1060}{13600}mmHg

P = 100mmHg+46.765mmHg

P = 146.765mmHg

Where,

\rho_{blood} = 1060Kg/m^3

\rho_{mercury}=13600Kg/m^3

Therefore the pressure is 146.765mmHg

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A hockey puck with a mass of 0.16 kg travels at a velocity of 40 m/s toward a goalkeeper. The goalkeeper has a mass of 120 kg an
Ainat [17]

Answer:

Explanation:

Momentum is the product of mass of a body and its velocity.

Given the mass of the puck m1 = 0.16kg

velocity of the puck v1 = 40m/s

Given the mass of the goalkeeper m2 = 120kg

velocity of the goalkeeper v2= 0m/s (goal keeper at rest)

The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is expressed as:

m1v1 + m2v2 (their momentum will be added since they collide)

= 0.16(40) + 120(0)

= 0.16(40) + 0

= 6.4kgm/s

Let us calculate their common velocity using the conservation of momentum formula;

m1u1 + m2u2 = (m1+m2)v

6.4 = (0.16+120)v

6.4 = 120.16v

v = 6.4/120.16

v = 0.053m/s

Hence after collision, both objects move at a velocity of 0.053m/s

Momentum of the puck after collision = m1v

Momentum of the puck after collision = 0.16*0.053m/s

Momentum of the puck after collision = 0.0085kgm/s

Momentum of the keeper after collision = m2v

Momentum of the keeper after collision = 120*0.053m/s

Momentum of the keeper after collision = 6.36kgm/s

From the calculation above, it can be seen that the keeper has the greater momentum after the puck was caught since the momentum of the keeper after collision is greater than that of the puck

4 0
2 years ago
A starship passes Earth at 80% of the speed of light and sends a drone ship forward at half the speed of light rela- tive to its
alisha [4.7K]

Answer:

Check Explanation

Explanation:

Let the speed of the drone relative to earth be u = ?

Let the speed of the drone relative to the starship be u' = 0.5c

Let the speed of the starship relative to earth be v = 0.8c

In the theory of relativity,

The 3 speeds are related thus

u = (u' + v)/[1 + (u'v/c²)]

u = (0.5c + 0.8c)[1 + ((0.8c × 0.5c)/c²)]

u = 1.3c/[1 + (0.4c²/c²)]

u = 1.3c/1.4 = 0.9286 c = 0.93 c = 93% c

8 0
2 years ago
A circuit is supplied with 60 VDC and contains two series resistors with values of 100 and 400 . What is the total current in th
scoundrel [369]

When resistors are connected in series, they act like
a single resistor whose resistance is their sum. 

100 ohms and 400 ohms, connected in series, look like
a single resistor of 500 ohms.

           Current = (voltage) / (resistance)

                        = (60 volts) / (500 ohms) = 0.12 A.
________________________
<span>
Current is measured by connecting a meter in series
with an energized component.  In other words, a break
is made in the circuit, the meter is connected in the break,
and the current to be measured literally flows through the meter.</span>

6 0
2 years ago
Two identical carts travel at the same speed toward each other, and then a collision occurs. The graphs show the momentum of eac
madam [21]

Explanation :

The interaction between two objects is termed as the collision. The collision can be of two types i.e. elastic collision and inelastic collision.

In this case, two identical carts travel at the same speed toward each other, and then a collision occurs. In an inelastic collision, the momentum before and after the collision remains the same but its kinetic energy gets lost.

After the collision, both the object sticks over each other and moves with one velocity.

Out of the given graph, the graph that shows a perfectly inelastic collision is attached. It shows that after the collision both the carts move with the same velocity.

5 0
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"You have been asked to design a "ballistic spring system" to measure the speed of bullets. A spring whose spring constant is k
e-lub [12.9K]

Answer:

In your question which ask to design a ballistic spring system to measure the speed of bullet. The ask is to find the expression for the bullets speed by using the term given in your question so base on the data you have given and with my calculation the answer is  (M+m)*g*d + 1/2*k*(d1-d)^2

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