The manometer shown in fig. 2 contains water and kerosene. with both tubes open to the atmosphere, the free-surface elevations d
1 answer:
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Answer:
(a) Height is 4.47 m
(b) Height is 4.37 m
Solution:
As per the question:
Initial velocity of teh ball,
Angle made by the ramp,
Distance traveled by the ball on the ramp, d = 5.00 m
Now,
(a) At any point on the projectile before attaining maximum height, the velocity can be given by the eqn-3 of motion:
where
H =
g =
= 19.06 m/s
Now, maximum height attained is given by:
Height from the ground =
(b) now, considering the coefficient of friction bhetween ramp and the ball, :
velocity can be given by the eqn-3 of motion:
= 18.7 m/s
Now, maximum height attained is given by:
Height from the ground =
Answer:
1 angstrom = 0.1nm
5000 angstrom = 5000/1 × 0.1nm
<h3>= 500nm</h3>5000 angstrom = 5000 × 1 × 10^-10
<h3>= 5 × 10^-7 m</h3>Hope this helps you