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2 years ago

The buoyant force on an object fully submerged in a liquid depends on (select all that apply)

1 answer:

8 0

The buoyant force on an object fully submerged in a liquid depends on
the density of the liquid, and the density of the object. But the density
of the object depends on the object's volume and the object's mass.

So the only item on this list that it DOESN't depend on is the mass of
the liquid.

I guess that means that the buoyant force on a fully submerged object is
the same whether it's submerged in a cup of water or the Pacific Ocean.

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What would the speed of each particle be if it had the same wavelength as a photon of yellow light (????=575.0 nm)? Proton (mass

PilotLPTM [1.2K]

Answer:

Proton: v=0.689 m/s

Neutron: v=0.688 m/s

Electron: v=1265.078 m/s

Alpha particle: v=0.173 m/s

Explanation:

De Broglie equation allows you to calculate the “wavelength” of an electron or any other particle or object of mass m that moves with velocity v:

λ= $\frac{h}{mv}$

h is the Planck constant: 6.626×10⁻³⁴ $\frac{kg.m^2}{s}$

We know that the wavelength of the particle is 575 nm (575×10⁻⁹m), so we find the velocity v for each particle:

λ= $\frac{h}{mv}$

v=h÷(mλ)

Proton:

m=1.673×10⁻²⁴ g · $\frac{1kg}{1000g}$ =1.673×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴ $\frac{kg.m^2}{s}$ ÷(1.673×10⁻²⁷ kg×575×10⁻⁹m)

v=0.689 m/s

Neutron:

m=1.675×10⁻²⁴ g · $\frac{1kg}{1000g}$ =1.675×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴ $\frac{kg.m^2}{s}$ ÷(1.675×10⁻²⁷ kg×575×10⁻⁹m)

v=0.688 m/s

Electron:

m= 9.109×10⁻²⁸ g · $\frac{1kg}{1000g}$ =9.109×10⁻³¹ kg

v=h÷(mλ)

v=6.626×10⁻³⁴ $\frac{kg.m^2}{s}$ ÷(9.109×10⁻³¹ kg×575×10⁻⁹m)

v=1265.078 m/s

Alpha particle:

m=6.645×10⁻²⁴ g · $\frac{1kg}{1000g}$ =6.645×10⁻²⁷ kg

v=h÷(mλ)

v=6.626×10⁻³⁴ $\frac{kg.m^2}{s}$ ÷(6.645×10⁻²⁷ kg×575×10⁻⁹m)

v=0.173 m/s

3 0

2 years ago

Read 2 more answers

Charge is distributed uniformly on the surface of a large flat plate. the electric field 2 cm from the plate is 30 n/c. the elec

AysviL [449]

The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
$E= \frac{\sigma}{2\epsilon_0}$
where
$\sigma$ is the charge density
$\epsilon_0$ is the vacuum permittivity

We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
$E=30 N/C$

7 0

2 years ago

Sophia is planning on going down an 8-m water slide. Her weight is 50 N. She knows that she has gravitational potential energy (

Pepsi [2]

Answer:The higher up an object is the greater its gravitational potential energy. The larger the distance something falls through the greater the amount of GPE the object loses as it falls. As most of this GPE gets changed into kinetic energy, the higher up the object starts from the faster it will be falling when it hits the ground. So a change in gravitational potential energy depends on the height an object moves through.

Explanation: Lifting an apple up 1 metre is easier work than lifting an apple tree the same height. This is because a tree has more mass, so it needs to be given more gravitational potential energy to reach the same height.

6 0

2 years ago

Find your mass if a scale on earth reads 650 N when you stand on it.

netineya [11]

Weight = (mass) x (gravity)

Acceleration of gravity on Earth = 9.8 m/s²

   Weight on Earth = (mass) x (9.8 m/s²)

Divide each side by (9.8 m/s²): Mass = (weight) / (9.8 m/s²)

    Mass = (650 N) / (9.8 m/s²)

   Mass = 66.33 kg (rounded)

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2 years ago

Daria was swimming in a friend’s pool yesterday, when she saw that a fly had landed in the water about 5 feet away from her. She

jasenka [17]

Answer:

Daria probably suffers from Entomophobia.

5 0

2 years ago