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maks197457 [2]
2 years ago
11

Trace fossils are recognized as evidence of which pre-existing life? plants plants and animals neither plants nor animals animal

s
Physics
2 answers:
photoshop1234 [79]2 years ago
5 0

Answer:

a fossil of a footprint, trail, burrow, or other trace of an animal rather than of the animal itself.

Explanation:

Trace fossils are the indirect evidence of life in the past, such as the footprints, tracks, burrows, borings, and feces left behind by animals, rather than the preserved remains of the actual animal body itself.

Fossil is the naturally preserved remains of plants and animals which somehow get trapped in amber, hair, petrified wood, oil, coal, and DNA remnants.

Kazeer [188]2 years ago
5 0

The correct answer is B. Plants and animals

Explanation:

Trae fossils refer to traces, prints of impressions of an organism that lived in the past, this occurs in the case the organism accidentally left an impression on a material that later hardens and remains over time. This also implies trace fossils only show the shape of an organism or parts of it but does not contain material fo the organism itself. This type of fossil has been used by scientists as evidence of past and extinct life forms included both animals and plants as fossils of reptiles, insects, fish, mammals, among others have been found but also fossils of some plants such as ferns.

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A seasoned mini golfer is trying to make par on a tricky number five hole. The golfer can complete the hole by hitting the ball
liberstina [14]

Answer:5.17 m/s

Explanation:

Given

let u be the speed at cliff initial point

range over cliff is 1.45 m

and range of projectile is given by

R=\frac{u^2\sin 2\theta }{g}

1.45=\frac{u^2\sin 90}{9.8}

u=3.77 m/s

Conserving Energy

E_{bottom}=E_{initial\ point\ at\ cliff}

Kinetic energy=Kinetic energy +Potential energy gained

Let v be the initial velocity

\frac{mv^2}{2}=mgh+\frac{mu^2}{2}

v^2=u^2+2gh

v=\sqrt{u^2+2gh}

v=\sqrt{3.77^2+2\time 9.8\times 0.64}

v=\sqrt{26.75}=5.17 m/s

5 0
1 year ago
A rescue helicopter wants to drop a package of supplies to isolated mountain climbers on a rocky ridge 200 m below. If the helic
andreev551 [17]

Answer:

a) 447.21m

b) -62.99 m/s

c)94.17 m/s

Explanation:

This situation we can divide in 2 parts:

⇒ Vertical : y =-200 m

y =1/2 at²

-200 = 1/2 *(-9.81)*t²

t= 6.388766 s

⇒Horizontal: Vx = Δx/Δt

Δx = 70 * 6.388766 = 447.21 m

b) ⇒ Horizontal

Vx = Δx/Δt ⇒ 70 = 400 /Δt

Δt= 5.7142857 s

⇒ Vertical:

y = v0t + 1/2 at²

-200 = v(5.7142857) + 1/2 *(-9.81) * 5.7142857²

v0= -7 m/s  ⇒ it's negative because it goes down.

v= v0 +at

v= -7 + (-9.81) * 5.7142857

v= -62.99 m/s

c) √(70² + 62.99²) = 94.17 m/s

8 0
2 years ago
A coworker did not clean his work area before going home this could cause an accident so you quickly clean up the next day you s
defon

Answer:

THE FIRST ONE YOU SHOULD TELL HIM AND THE LAST ONE YOU SHOUDENT DO BECAUSE HE WILL DO IT AGAIN AND EXPECT OTHERS TO CLEAN UP AFTER HIM

Explanation:

5 0
1 year ago
Read 2 more answers
Medical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e
Arlecino [84]

Answer:

The radius is r =  4.434 *10^{-5} \ m

Explanation:

From the question we are told that

    The magnetic field is  B =   90 mT =  90*10^{-3} \ T

     The electron kinetic energy is  KE  =  1.4 eV = 1.4 * (1.60*10^{-19})  =2.24*10^{-19} \ J

Generally for the collision to occur the centripetal force of the electron in it orbit is equal to the magnetic force applied  

   This is mathematically represented as

   \frac{mv^2}{r}  =  qvB

=>    r =  \frac{m* v}{q *  B}

Where  m is the mass of electron with values m  =  9.1 *10^{-31} \ kg  

             v is the escape velocity  which is mathematically represented as

                v  = \sqrt{\frac{2 * KE}{m} }

So  

       r =  \frac{m}{qB}  *  \sqrt{\frac{2 *  KE}{m} }

     apply indices

    r = \frac{\sqrt{2 * KE * m} }{qB}

substituting values

   

        r = \frac{\sqrt{2 * 2.24*10^{-19}* 9.1 *10^{-31}} }{ 1.60 *10^{-19}* 90*10^{-3}}

       r =  4.434 *10^{-5} \ m

     

6 0
1 year ago
One of the Lady Spartans was falling to the ground after
dem82 [27]

Answer:

Explanation:

Given that,

A lady falling has a final velocity of 4m/s

v = 4m/s

Mass of the lady is 60kg.

m = 60kg

Using conservation of energy, the potential energy of the body from the point where the lady is dropping is converted to the final kinetic energy of the lady.

Therefore,

P.E = K.E(final) = ½mv²

P.E = ½ × 60 × 4²

P.E = 480 J.

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1 year ago
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