Trace fossils are recognized as evidence of which pre-existing life? plants plants and animals neither plants nor animals animal
2 answers:
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Answer:
a) the mug hits the floor 0.7425m away from the end of the bar. b) |V|=5.08m/s θ= -72.82°
Explanation:
In order to solve this problem, we must first start by doing a drawing of the situation. (see attached picture).
a)
From the drawing we can see that we are dealing with a two dimensions movement problem. So in order to find out how far away from the bar the mug will fall, we need to start by finding how long it will take the mug to be in the air, so we analyze the vertical movement of the mug.
In order to find the time we need to use the following formula, which contains the data we know:
we know that and that
as well, so the formula is simplified to:
we can now solve this for t, so we get:
we know that and that
the acceleration of gravity is negative because the mug is moving downwards. So we substitute them into the given formula:
which yields:
t=0.495s
we can now use this to find the horizontal distance the mug travels. We know that:
so we can solve this for x, so we get:
and we can now substitute the values we know:
x=(1.5m/s)(0.495s)
which yields:
x=0.7425m
b) Now that we know the time it takes the mug to hit the floor, we can use it to find the final velocity in the y-direction by using the following formula:
we know the initial velocity in the vertical direction is zero, so we can simplify the formula:
so we can solve this for the final velocity:
in this case the acceleration is the same as the acceleration of gravity (which is negative) so we can substitute that and the time we found on the previous part to get:
which yields:
so now we know the components of the final velocity, which are:
and
so now we can find the speed by determining the magnitude of the vector, like this:
so we get:
which yields:
|V|=5.08m/s
now, to find the direction of the impact, we can use the following equation:
so we get:
which yields:
Answer:
The speed in the first point is: 4.98m/s
The acceleration is: 1.67m/s^2
The prior distance from the first point is: 7.42m
Explanation:
For part a and b:
We have a system with two equations and two variables.
We have these data:
X = distance = 60m
t = time = 6.0s
Sf = Final speed = 15m/s
And We need to find:
So = Inicial speed
a = aceleration
We are going to use these equation:
We are going to put our data:
With these equation, you can decide a method for solve. In this case, We are going to use an egualiazation method.
If we analyze the situation, we need to have an aceleretarion greater than cero. We are going to choose a = 1.67m/s^2
After, we are going to determine the speed in the first point:
For part c:
We are going to use: