answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irina1246 [14]
2 years ago
13

Walter Arfeuille of Belgium lifted a 281.5 kg load off the ground using his teeth. Suppose Arfeuille can hold just three times t

hat mass on a 30.0° slope using the same force. What is the coefficient of static friction between the load and the slope?
Physics
2 answers:
Umnica [9.8K]2 years ago
6 0
Gravitational, g = 9.81 m/s2 
Theta = 30 degrees, using the same force. 
Let u be the coefficient of static friction 
Force applied F = mg 
Static Friction Force = u3mgcos (theta) 
The gravitational Force = 3mgsin (theta) 
So the force equation = 3mgsin (theta) - (u3mgcos (theta) + mg) = 0 
So 3mgsin (theta) = (u3mgcos (theta) + mg) => 3sin (theta) = (u3cos (theta) + 1)
 => u = (3sin (30) - 1) / 3cos (30) => u = (3(1/2) - 1) / (3 x 0.866)
 => u = (1.5 - 1) / 2.59 = 0.5 / 2.59 = 0.5 / 2.598
 Coefficient of Static Friction u = 0.19.
Alecsey [184]2 years ago
5 0
Let's call
 m = 281.5Kg
 The force that Walter can make is by definition:
 F = m * g
 where,
 g: acceleration of gravity.
 Suppose Walter is at the top of the slope:
 By making a free-body diagram we have the following forces in the direction of the slope:
 Friction force = (μ3mgcosø)
 Force of gravity = (3mgsinø),
 Force exerted by Walter = mg
 We have then:
 mg + μ3mgcosø-3mgsinø = 0.
 Clearing the friction coefficient:
 μ = (3sinø-1) / (3cosø).
 Substituting the angle:
 μ = 0.19.
 answer
 the coefficient of static friction between the load and the slope is 0.19
You might be interested in
what is the acceleration of a bowling ball that starts at rest and moves 300m down the gutter in 22.4 sec
exis [7]
<span>Acceleration is the change in velocity divided by time taken. It has both magnitude and direction. In this problem, the change in velocity would first have to be calculated. Velocity is distance divided by time. Therefore, the velocity here would be 300 m divided by 22.4 seconds. This gives a velocity of 13.3928 m/s. Since acceleration is velocity divided by time, it would be 13.3928 divided by 22.4, giving a final solution of 0.598 m/s^2.</span>
7 0
2 years ago
The amplitude of a lightly damped oscillator decreases by 3.0% during each cycle. what percentage of the mechanical energy of th
Zanzabum

E = ½KA^2 is the mechanical energy of any oscillator.  It is the sum of elastic potential energy and kinetic energy.  When amplitude A decreases by 3%, then

(E2-E1)/E1 = {½K(A2^2/A1^2) }/ ½K(A1^2)

= {(A2^2 – A1^2) / (A1^2)}

= 97^2 – 100^2/100^2

= 5.91% of the mechanical energy is lost each cycle.

3 0
1 year ago
An astronomer observes that the wavelength of light from a distant star is shifted toward the red part of the visible spectrum.
balandron [24]

Answer:

The distance between the earth and the star is increasing.

Explanation:

When we observe an object and its electromagnetic radiation has been displaced to blue, it means that it is getting closer to us, causing the light waves it emits to get closer together and its wavelength to decrease towards blue, this is knowm as blueshift.

On the contrary, when an object is rapidly moving away from us, the light waves or electromagnetic radiation it emits have been stretched from their normal wavelength to a longer wavelength, towards the red part of the spectrum. This is known as redshift.

This phenomenon of changes in wavelength and frequency due to movement (whether the source approaches or moves away) is described by the Doppler effect.

So for this case because the light we perceive from the star has moved to the red part of the visible spectrum, we can conclude that it is moving away from the earth, and that the distance between the star and the earth is increasing.

7 0
2 years ago
. Emergency rations are to be dropped from a plane to some stranded hikers. The search and rescue plane is flying at an altitude
almond37 [142]

Answer:

35 m/s down

Explanation:

The horizontal speed of the package is 70 m/s.  So the time needed to reach the hikers is:

1000 m / (70 m/s) = 14.28 s

Taking down to be positive, the initial velocity needed is:

Δy = v₀ t + ½ at²

1500 m = v₀ (14.28 s) + ½ (9.8 m/s²) (14.28 s)²

v₀ = 35 m/s

The package must be launched down with an initial velocity of 35 m/s.

3 0
2 years ago
Read 2 more answers
Which is found farthest from the center of an atom?
xxTIMURxx [149]
Electron

Hope this helps
5 0
1 year ago
Other questions:
  • A 16-kg scooter is moving at a speed of 7 m/s. The scooter’s speed doubles. What is the scooter’s kinetic energy when its speed
    5·1 answer
  • Consider a steel guitar string of initial length l=1.00m and cross-sectional area a=0.500mm2. the young's modulus of the steel i
    7·1 answer
  • While looking at bromine (Br) on the periodic table, a student needs to find another element with very similar chemical properti
    13·2 answers
  • How much heat is released when 432 g of water cools down from 71'c to 18'c?
    13·1 answer
  • A tennis ball is dropped from 1.20 m above the ground. It rebounds to a height of 1.00 m. (a) with what velocity does it hit the
    7·1 answer
  • The Sun is the primary source of energy for ecosystems. The Sun emits . When an organism obtains nutrients by feeding on other o
    7·2 answers
  • You lower the temperature of a sample of liquid carbon disulfide from 90.3 ∘ C until its volume contracts by 0.507 % of its init
    5·2 answers
  • A 10 kg migratory swan cruises at 20 m/s. A calculation that takes into ac- count the necessary forces shows that this motion re
    9·1 answer
  • When laser light shines on a screen after passing through two closely spaced slits, it becomes
    9·1 answer
  • In an experiment, students release a block from rest at the top of an inclined plane. The block slides down the plane through a
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!