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anzhelika [568]
2 years ago
12

A sample of a gas has a volume of 639 cm3 when the pressure is 75.9 kPa. What is the volume of the gas when the pressure is incr

eased to 125 kPa if the temperature remains constant? *
Physics
1 answer:
const2013 [10]2 years ago
7 0

Answer:

388 cm^3

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

pV=const.

which can also be rewritten as

p_1 V_1 = p_2 V_2

In our case, we have:

p_1 = 75.9 kPa is the initial pressure

V_1 = 639 cm^3 is the initial volume

p_2 = 125 kPa is the final pressure

Solving for V2, we find the final volume:

v_2 = \frac{p_1 V_1}{p_2}=\frac{(75.9)(639)}{125}=388 cm^3

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When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion. Which o
Setler [38]

<u>Answer:</u>

Option: D. Gravity is pulling the crash test dummy in the direction the car is moving.

<u>Explanation: </u>

When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion because the gravity is pulling the crash test dummy in the direction the car is moving.  

Basically when the car is starting, the person inside is in static position and the car is going to move. So it is putting a force on the person to move on the same speed. But as the person is sitting static hence gravity is pulling him behind from moving. Hence, The dummy appears to be pressed backward.

7 0
2 years ago
A machine part is vibrating along the x-axis in simple harmonic motion with a period of 0.27 s and a range (from the maximum in
Gnoma [55]

Answer:

x = -1.437 cm

Explanation:

The general equation for position of Simple harmonic motion is given as:

x = A sin(\omega t)          ........(1)

where,

x = Position of the wave

A = Amplitude of the wave

ω = Angular velocity

t = time

In this case, the amplitude is just half the range,

thus,

A =\frac{3cm}{2}=1.5cm  (Given range = 3cm)

A = 1.5 cm  

Now, The angular velocity is given as:

\omega=\frac{2\pi}{T}

Where, T = time period of the wave =0.27s (given)

\omega=\frac{2\pi}{0.27s}

or

\omega=23.27s^{-1}

so, at time t = 55 s, the equation (1) becomes as:

x = 1.5 sin(23.27\times 55)

on solving the above equation we get,

x = -1.437 cm

here the negative sign depicts the position in the opposite direction of +x

5 0
2 years ago
. A horizontal steel spring has a spring constant of 40.0 N/m. What force must be applied to the spring in order to compress it
ANEK [815]

Ans    4 more to be exact

Explanation:

7 0
2 years ago
If period of the pendulum in preceding sample problem were 24s how tall would the tower be ?
frutty [35]

Answer:

So length of pendulum is 143.129 m

Explanation:

We have given period of simple pendulum is 2 sec

We have to find the length of simple pendulum

Let the length of pendulum is l

Acceleration due to gravityg=9.8m/sec^2 is

Time period is given by T=2\pi \sqrt{\frac{l}{g}}

So 24=2\times 3.14\times  \sqrt{\frac{l}{9.8}}

\sqrt{\frac{l}{9.8}}=3.821

Squaring both side

{\frac{l}{9.8}}=14.60

l =143.129 m

So length of pendulum is 143.129 m

8 0
2 years ago
Read 2 more answers
If a scale on Earth reads 650 N, what is your mass?
OlgaM077 [116]
If the scale reads 650N, then the mass of whoever it is standing on the scale is

         (weight) / (gravity)  =  (650N) / (9.8 m/s²)  =  66.3 kilograms  .

It's not MY mass, even if I'm the one standing on the scale. 
If I stand on a scale and it reads 650 N, the scale is broken.
4 0
2 years ago
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