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2 years ago

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A projectile was launched horizontally with a velocity of 468 m/s, 1.86 m above the ground. Calculate how long it would take for

the projectile to hit the ground, to the nearest tenth of a second. Record your answer in the boxes below. Be sure to use the correct place value.

2 answers:

elena-14-01-66 [18.8K]2 years ago

5 0

Answer:

0.6 seconds

Explanation:

The time to fall from height h is ...

t = √(2h/g)

t = √(2(1.86 m)/(9.8 m/s^2)) ≈ √0.3796 s ≈ 0.616 s

It would take about 0.6 seconds for the projectile to hit the ground.

nata0808 [166]2 years ago

5 0

Answer:

<em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u> </u></em><em><u>seconds</u></em><em><u> </u></em>

<em><u>is</u></em><em><u> </u></em><em><u>ur</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>)</u></em><em><u> </u></em>

<em><u /></em><em><u>✌</u></em><em><u>❤</u></em>

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Answer:

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