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avanturin [10]
2 years ago
14

A projectile was launched horizontally with a velocity of 468 m/s, 1.86 m above the ground. Calculate how long it would take for

the projectile to hit the ground, to the nearest tenth of a second. Record your answer in the boxes below. Be sure to use the correct place value.
Physics
2 answers:
elena-14-01-66 [18.8K]2 years ago
5 0

Answer:

  0.6 seconds

Explanation:

The time to fall from height h is ...

  t = √(2h/g)

  t = √(2(1.86 m)/(9.8 m/s^2)) ≈ √0.3796 s ≈ 0.616 s

It would take about 0.6 seconds for the projectile to hit the ground.

nata0808 [166]2 years ago
5 0

Answer:

<em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u> </u></em><em><u>seconds</u></em><em><u> </u></em>

<em><u>is</u></em><em><u> </u></em><em><u>ur</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>)</u></em><em><u> </u></em>

<em><u /></em><em><u>✌</u></em><em><u>❤</u></em>

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Who pays for Government workers that work on alcohol impaired driving cases?
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Explanation:

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Suppose a rectangular piece of aluminum has a length D, and its square cross section has the dimensions W XW, where D (W x W) to
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Answer:

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Before a collision, the x-momentum of an object is 8.0 × 103 kilogram meters/second, and its y-momentum is 1.2 × 104 kilogram me
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A bee wants to fly to a flower located due North of the hive on a windy day. The wind blows from East to West at speed 6.68 m/s.
Aleonysh [2.5K]

Answer:  53.31\° East of North

Explanation:

We have the following data:

Speed of the wind from East to West: 6.68 m/s

Speed of the bee relative to the air:  8.33 m/s

If we graph these speeds (which in fact are velocities because are vectors) in a vector diagram, we will have a right triangle in which the airspeed of the bee (its speed relative to te air) is the hypotense and the two sides of the triangle will be the <u>Speed of the wind from East to West</u> (in the horintal part) and the <u>speed due North relative to the ground</u> (in the vertical part).

Now, we need to find the direction the bee should fly directly to the flower (due North):

sin \theta=\frac{Windspeed-from-East-to-West}{Speed-bee-relative-to-air}

sin \theta=\frac{6.68 m/s}{8.33 m/s}

Clearing \theta:

\theta=sin^{-1} (\frac{6.68 m/s}{8.33 m/s})

\theta=53.31\°

6 0
2 years ago
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