Answer: the answer is d
Explanation: there are not more than 10 violations within a twelve month period hope this helps
Incomplete question.The complete question is here
What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade? The outer edge of the blade is 21 cm from the center of the blade, and the mass of the outer portion is 7.7 g. Even though the blade is 21cm long, the last 2cm should be treated as if they were at a point 20cm from the center of rotation.
Answer:
F= 0.034 N
Explanation:
Given Data
Outer=2 cm
Edge of blade=21 cm
Mass=7.7 g
Length of blade=21 cm
The last 2cm is treated as if they were at a point 20cm from the center of rotation
To Find
Force=?
Solution
Convert the given frequency to angular frequency
ω = 45 rpm * (2*pi rad / 1 rev) * (1 min / 60 s)
ω= 3/2*π rad/sec
Now to find centripetal force.
F = m×v²/r
F= m×ω²×r
Put the data
F = 0.0077 kg × (3/2×π rad/sec
)²× 0.20 m
F= 0.034 N
Answer:
N = 23.4 N
Explanation:
After reading that long sentence, let's solve the question
The contact force is the so-called normal in this case we can find it by writing the translational equilibrium equation for the y axis
N - w₁ -w₂ =
N = m₁ g + m₂ g
N = g (m₁ + m₂)
let's calculate
N = 9.8 (0.760 + 1.630)
N = 23.4 N
This is the force of the support of the two blocks on the surface.
Answer:
30.93 m/s
Explanation:
Given that, the speed of stolen car is,

As policeman start chasing the stolen car after 60 seconds.
Now suppose the speed of policeman car is, 
The policeman catches the stolen car at a distance of,

Now the distance covered by the policeman in time t is 
And the distane cover by the thief in stolen car in time(t+60s) is
.
And these distances are equal and they are equal to 60000 m.
Therefore,

Therfore,

Now use this value to solve for minimum speed of policeman's car.

Therefore minimum speed of policeman's car is 30.93 m/s.
molecular weights are written in the picture.
CH4<NH3<H2O<Cl2