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anastassius [24]
2 years ago
9

An object is thrown horizontally off a cliff with an initial velocity of 5.0 meters per second. the object strikes the ground 3

seconds later. what is the horizontal speed of the object 1.0 second after it is released
Physics
2 answers:
ki77a [65]2 years ago
8 0

Answer: Horizontal speed=5m/s

Explanation:

Speed= distance / time

Speed of object = 5m/s

Distance = 5m/s/1second= 5m

Speed = 5m× 1sec=5m/s

Horizontal speed after 1 second is 5m/s

shutvik [7]2 years ago
7 0
Speed is not a vector so horizontal speed does not sighify anything. If u meant velocity it vill be same as the initial velocity in horizontal direction
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The actions of an employee are not attributable to the employer if the employer has not directly or indirectly encouraged the em
zepelin [54]

Answer:    the answer is d

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4 0
2 years ago
What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade?
kaheart [24]

Incomplete question.The complete question is here

What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade? The outer edge of the blade is 21 cm from the center of the blade, and the mass of the outer portion is 7.7 g. Even though the blade is 21cm long, the last 2cm should be treated as if they were at a point 20cm from the center of rotation.

Answer:

F= 0.034 N

Explanation:

Given Data

Outer=2 cm

Edge of blade=21 cm

Mass=7.7 g

Length of blade=21 cm

The last 2cm is treated as if they were at a point 20cm from the center of rotation

To Find

Force=?

Solution

Convert the given frequency to angular frequency

ω = 45 rpm * (2*pi rad / 1 rev) * (1 min / 60 s)

ω= 3/2*π rad/sec

Now to find centripetal force.

F = m×v²/r

F= m×ω²×r

Put the data

F = 0.0077 kg × (3/2×π rad/sec )²× 0.20 m

F= 0.034 N

3 0
2 years ago
This is a problem about a child pushing a stack of two blocks along a horizontal floor. The masses of the blocks, and the coeffi
Rufina [12.5K]

Answer:

 N = 23.4 N

Explanation:

After reading that long sentence, let's solve the question

The contact force is the so-called normal in this case we can find it by writing the translational equilibrium equation for the y axis

            N - w₁ -w₂ =

            N = m₁ g + m₂ g

            N = g (m₁ + m₂)

let's calculate

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7 0
1 year ago
A policeman starts giving chase 60 seconds after a stolen car zooms by at 108 km/hr. At what minimum speed should he drive if he
Iteru [2.4K]

Answer:

30.93 m/s

Explanation:

Given that, the speed of stolen car is,

v_{s} =108km/hr\\v_{s} =108\times \frac{5}{18}m/s\\ v_{s} =30m/s

As policeman start chasing the stolen car after 60 seconds.

Now suppose the speed of policeman car is, v_{p}

The policeman catches the stolen car at a distance of,

S=60km\\S=60000m

Now the distance covered by the policeman in time t is v_{p}\times t

And the distane cover by the thief in stolen car in time(t+60s) is v_{s}\times (t+60sec).

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Therefore,

v_{p}\times t=v_{s}\times (t+60sec)=60000m

Therfore,

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Now use this value to solve for minimum speed of policeman's car.

v_{p}\times 1940=60000\\v_{p}=30.93 m/s

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6 0
2 years ago
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molecular weights are written in the picture.

CH4<NH3<H2O<Cl2

6 0
1 year ago
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