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2 years ago

When calculating the mechanical advantage of a lever, what two pieces of information are needed?

2 answers:

4 0

From the items on this list, the only one that allows calculation
of the mechanical advantage is 'B' ... the lengths from the fulcrum
to the effort and the resistance.

The MA can also be calculated when you know the two forces ...
the effort and the resistance ... when the lever is just balanced.

Shkiper50 [21]2 years ago

3 0

Answer:

Option B)

the length of the effort arm and the length of the resistance arm

Explanation:

A lever is a simple machine with a point fulcrum known also as a hinge. The lever helps to rotate the body and vary the input force and output force to get maximum mechanical advantage.

Mechanical advantage of a lever is the ratio of the output force to input force.

When there is no friction or other forces this mechanical advantage can also be calculated as the ratio of length of effort arm to length of resistance arm.

Hence option B is right.

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Ugonna stands at the top of an incline and pushes a 100−kg crate to get it started sliding down the incline. The crate slows to

Anna [14]

Answer:(a)891.64 N

(b)0.7

Explanation:

Mass of crate $m=100 kg$

Crate slows down in $s=1.5 m$

initial speed $u=1.77 m/s$

inclination $\theta =30^{\circ}$

From Work-Energy Principle

Work done by all the Forces is equal to change in Kinetic Energy

$W_{friction}+W_{gravity}=\frac{1}{2}mv_i^2-\frac{1}{2}mv_f^2$

$W_{gravity}=mg(0-h)=mgs\sin \theta$

$W_{gravity}=-mgs\sin \theta$

$W_{gravity}=-100\times 9.8\times 1.5\sin 30=-735 N$

change in kinetic energy $=\frac{1}{2}\times 100\times 1.77^2=156.64 J$

$W_{friction}=156.64+735=891.645$

(b)Coefficient of sliding friction

$f_r\cdot s=W_{friciton}$

$891.645=f_r\times 1.5$

$f_r=594.43 N$

and $f_r=\mu mg\cos \theta$

$\mu 100\times 9.8\times \cos 30=594.43$

$\mu =0.7$

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2 years ago

568 muons were counted by a detector on the top of Mount Washington in a one hour period of time. Assuming moving muons keep tim

AlladinOne [14]

The answer to this question is:

C-"That moving clocks run slower"

Your Welcome :)

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2 years ago

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Several charges in the neighborhood of point P produce an electric potential of 6.0 kV (relative to zero at infinity) and an ele

Julli [10]

Answer:

0.018 J

Explanation:

The work done to bring the charge from infinity to point P is equal to the change in electric potential energy of the charge - so it is given by

$W = q \Delta V$

where

$q=3.0 \mu C = 3.0 \cdot 10^{-6} C$ is the magnitude of the charge

$\Delta V = 6.0 kV = 6000 V$ is the potential difference between point P and infinity

Substituting into the equation, we find

$W=(3.0\cdot 10^{-6}C)(6000 V)=0.018 J$

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2 years ago

An experiment consists of determining the speed of automobiles on a highway by the use of radar equipment. The random variable i

faust18 [17]

The random variable in this experiment is a Continuous random variable.

Option D

<u>Explanation</u>:

The continuous random variable is random variable where the data can take infinite variables. For example random variable is taken for measuring "speed of automobiles" on the highways. The radar instrument depicts time taken by automobile in particular what speed. They are the generalization of discrete random variables not the real numbers as a random data is created. It gives infinite sets of all possible outcomes. It is obvious that outcomes of the instrument depend on some "physical variables" those are not predictable as depends on the situation.

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2 years ago

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If a 1000-pound capsule weighs only 165 pounds on the moon, how much work is done in propelling this capsule out of the moon's g

yulyashka [42]

Answer:

178200 g mile pounds

Explanation:

Work= Force * Distance= Fh

F=ma=mg where m is mass and g is acceleration due to gravity

Work= 165 pounds *g* 1080 m= 178200 g mile pounds

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2 years ago