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topjm [15]
2 years ago
8

568 muons were counted by a detector on the top of Mount Washington in a one hour period of time. Assuming moving muons keep tim

e at the same rate as stationary muons, then 27 should survive until sea level. The fact that 412 muons were detected by the same equipment at sea level reveals that
A. the stationary clock measures time differently at different altitudes
B. the moving clocks keep time at the same rate as stationary clocks
C. that moving clocks run slower
D. that moving clocks run faster
Physics
2 answers:
AlladinOne [14]2 years ago
6 0
The answer to this question is:

C-"That moving clocks run slower"

Your Welcome :)
Cerrena [4.2K]2 years ago
4 0

Explanation:

The fact that 412 muons were detected by the same equipment at sea level reveals that moving clocks run slower. This is due to the reason of time dilation.

The time dilation slow down time with respect to external observer. The time dilation is caused due to the force of gravity and the velocity with which the object is moving.

Hence, the correct option is (c) "moving clocks run slower".

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Consider two circular metal wire loops each carrying the same current I as shown below. In what r... Consider two circular metal
NeX [460]

Answer:

1) The magnetic field outside the loop is zero.

In region III the magnetic fields due to the two wire loops point in the opposite direction andhence cancel each other. Therefore the magnetic field is zero in region I, III and V

The diagram is attached

6 0
2 years ago
A front wheel drive car starts from rest and accelerates to the right. Knowing that the tires do not slip on the road, what is t
Korolek [52]

Answer:

static friction acting opposite to the direction of travel

Explanation:

Because the Frictional force of the front wheels act to oppose the spinning, so, For the front wheels to roll without slipping, the friction must be static friction pointing in the direction of travel of the car.

Explanation:

8 0
2 years ago
Charge q1 is distance r from a positive point charge q. charge q2=q1/3 is distance 2r from q. what is the ratio u1/u2 of their p
makvit [3.9K]
We need the power law for the change in potential energy (due to the Coulomb force) in bringing a charge q from infinity to distance r from charge Q. We are only interested in the ratio U₁/U₂, so I'm not going to bother with constants (like the permittivity of space). 

<span>The potential energy of charge q is proportional to </span>
<span>∫[s=r to ∞] qQs⁻²ds = -qQs⁻¹|[s=r to ∞] = qQr⁻¹, </span>

<span>so if r₂ = 3r₁ and q₂ = q₁/4, then </span>
<span>U₁/U₂ = q₁Qr₂/(r₁q₂Q) = (q₁/q₂)(r₂/r₁) </span>
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5 0
2 years ago
Two wires are stretched between two fixed supports and have the same length. One wire A there is a second-harmonic standing wave
lina2011 [118]

(a) Greater

The frequency of the nth-harmonic on a string is an integer multiple of the fundamental frequency, f_1:

f_n = n f_1

So we have:

- On wire A, the second-harmonic has frequency of f_2 = 660 Hz, so the fundamental frequency is:

f_1 = \frac{f_2}{2}=\frac{660 Hz}{2}=330 Hz

- On wire B, the third-harmonic has frequency of f_3 = 660 Hz, so the fundamental frequency is

f_1 = \frac{f_3}{3}=\frac{660 Hz}{3}=220 Hz

So, the fundamental frequency of wire A is greater than the fundamental frequency of wire B.

(b) f_1 = \frac{v}{2L}

For standing waves on a string, the fundamental frequency is given by the formula:

f_1 = \frac{v}{2L}

where

v is the speed at which the waves travel back and forth on the wire

L is the length of the string

(c) Greater speed on wire A

We can solve the formula of the fundamental frequency for v, the speed of the wave:

v=2Lf_1

We know that the two wires have same length L. For wire A, f_1 = 330 Hz, while for wave B, f_B = 220 Hz, so we can write the ratio between the speeds of the waves in the two wires:

\frac{v_A}{v_B}=\frac{2L(330 Hz)}{2L(220 Hz)}=\frac{3}{2}

So, the waves travel faster on wire A.

7 0
2 years ago
The simulation kept track of the variables and automatically recorded data on object displacement, velocity, and momentum. If th
DiKsa [7]
<h2><u>Answer:</u></h2>

The simulation kept track of the variables and automatically recorded data on object displacement, velocity, and momentum. If the trials were run on a real track with real gliders, using stopwatches and meter sticks for measurement, the data compared by the following statements:

1. (There would be variables that would be hard to control, leading to less reliable data.)

3. (Meter sticks may lack precision or may be read incorrectly.)

4. (Real glider data may vary since real collisions may involve loss of energy.)

5. (Human error in recording or plotting the data could be a factor.)


6 0
2 years ago
Read 2 more answers
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