Answer:
the answer is 30°
Explanation:
due to:
sin law of sines
The particle starts from rest at t=0. What is the magnitude p of the momentum of the particle at time t? Assume that t>0. Exp
1 answer:
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Answer:
Speed of water, v = 4.2 m/s
Explanation:
Given that,
Diameter of the tank, d = 17 cm
It is placed at a height of 90 cm, h = 0.9 m
We need to find the speed at which the water exits the tank through the hole. It can be calculated using the conservation of energy as :
v = 4.2 m/s
So, the speed of water at which the water exits the tank through the hole is 4.2 m/s. Hence, this is the required solution.
Answer:
So No of slices to be consumed by each person = n = 65
Explanation:
Energy released by one slice = E1
h = 8850 m ; m = 79 kg ,η= 10.5%
We know that potential energy given as
u = m g h
u = 79 x 9.81 x 8850
we know from the defination of efficiency that, η= E(out)/E(in)
Now amount of PE has to be compensated, In our case, E(out) =u
Let n be the number of bread slices to be consumed.
n = E(in)/E1
n=64.76
So No of slices to be consumed by each person = n = 65
Answer: Hello there!
We know this:
The distance between the cars at t= 0 is D.
car 2 has an initial velocity of v0 and no acceleration.
car 1 has no initial velocity and a acceleration of ax that starts at t = 0
then we could obtain the acceleration of the car 1 by integrating the acceleration over the time; this is v(t) = ax*t where there is not a constant of integration because the car 1 has no initial velocity.
Because the cars are moving against each other, we want to se at what time t they meet, this is equivalent to see:
position of car 1 + position of car 2 = D
and in this way we could ignore constants of integration :D
for the position of each car we integrate again:
P1(t) = (1/2)ax*t^2 and P2(t) = v0t
v0t + (1/2)ax*t^2 = D
v0t + (1/2)ax*t^2 - D = 0
now we can solve it for t using the Bhaskara equation.
that we cant solve witout knowing the values for v0, D and ax. But you could replace them in that equation and obtain the time, where you must remember that you need to choose the positive solution (because this quadratic equation has two solutions).
Now we want to know the velocity of car 1 just before the impact, this can be calculated by valuating the time in the as the time that we just found in the velocity equation for the car 1, this is:
where again, you need to replace the values of v0, D and ax.