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gavmur [86]
2 years ago
7

How much force is required to pull a spring 3.0 cm from

Physics
1 answer:
avanturin [10]2 years ago
4 0

Answer:

I know that T= kx where T is the tension which equaka the force og gravity = mg = 1.37 * 10 = 13.7 x is the elongation of the spring so the length after dangling the object minus the original length.

I hope it helps

plz let me know if it is wrong or right.

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Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The mass o
insens350 [35]

Answer:

295.42 N

Explanation:

From Newton's law of universal gravitation.

F = Gmm'/r².................. Equation 1

Where F = Gravitational force, G = Universal constant, m = mass of the human, m' = mass of mass, r = radius of mass.

Given: m = 80 kg, m' = 6.4×10²³ kg, r = 3.4×10⁶ m.

Constant: G = 6.67×10⁻¹¹ Nm²/Kg²

Substitute into equation 1

F =  6.67×10⁻¹¹(80)(6.4×10²³ )/( 3.4×10⁶)²

F = 3415.04×10¹²/(11.56×10¹²)

F = 3415.04/11.56

F = 295.42 N

Hence the gravitational force =  295.42 N

5 0
2 years ago
Deep-sea divers often breathe a mixture of helium and oxygen to avoid getting the "bends" from breathing high-pressure nitrogen.
kvv77 [185]

Answer:

0.69444 m, 0.08152 m, 0.32407 m, 0.03804 m

Explanation:

v = Velocity of sound

f = Frequency

Length of vocal tract is given by

L=\dfrac{v}{4f}

At f = 270 Hz v = 750 m/s

L=\dfrac{750}{4\times 270}\\\Rightarrow L=0.69444\ m

At f = 2300 Hz v = 750 m/s

L=\dfrac{750}{4\times 2300}\\\Rightarrow L=0.08152\ m

At f = 270 Hz v = 350 m/s

L=\dfrac{350}{4\times 270}\\\Rightarrow L=0.32407\ m

At f = 2300 Hz v = 350 m/s

L=\dfrac{350}{4\times 2300}\\\Rightarrow L=0.03804\ m

3 0
1 year ago
Two particles collide and stick together. If no external forces act on the two particles, which of the following is correct for
Semmy [17]

Answer:

c.\Delta p=0 and \Delta k

Explanation:

We are given that two particles collide  and stick together.

If there is no external force act on the two particles then ,it is inelastic collision.

Inelastic collision: There is some loss of kinetic energy but the momentum is conserved.

According to law of conservation of momentum

Initial momentum=Final momentum

Change in momentum=Final momentum-Initial momentum=0

Change in momentum=\Delta p=0

Initial kinetic energy is greater than final kinetic energy.

Change in kinetic energy=Final kinetic energy-kinetic energy=- negative

\Delta k

Hence, option c is true.

c.\Delta p=0 and \Delta k

4 0
1 year ago
On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the
EastWind [94]

Answer:

ω = √(2T / (mL))

Explanation:

(a) Draw a free body diagram of the mass.  There are two tension forces, one pulling down and left, the other pulling down and right.

The x-components of the tension forces cancel each other out, so the net force is in the y direction:

∑F = -2T sin θ, where θ is the angle from the horizontal.

For small angles, sin θ ≈ tan θ.

∑F = -2T tan θ

∑F = -2T (Δy / L)

(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m).  (This is derived by solving a second order differential equation.)

In this case, k = 2T/L, so the frequency is:

ω = √((2T/L) / m)

ω = √(2T / (mL))

6 0
2 years ago
Compare the benefits of wildfires to grasslands, northern forests, and deciduous forests.
Dimas [21]
Wildfires benefit grasslands, northern forests, and deciduous forests. Grasslands are benefited by improved soil quality and control of tree cover. Invertebrate species diversity is maintained through wildfire as well. Northern forests, like grasslands, experience increased production and nutritional quality of food as a result of wildfires. Deciduous forests experience an increase in the nutritional quality of food as well, but the effects are more temporary. The amount of shrubs in deciduous forests is reduced as a result of wildfires, allowing more herbaceous plants such as mosses and lichens to grow.
6 0
2 years ago
Read 2 more answers
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