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Sergeu [11.5K]
2 years ago
15

If the soccer player runs with a speed of 4.6m/s, how long does it take him to run 60m?

Physics
2 answers:
Diano4ka-milaya [45]2 years ago
7 0
About 13 s (60/4.6)
satela [25.4K]2 years ago
5 0

Explanation:

Hello there!

Just divide 60 by 4.6:

60/4.6=13.04 seconds.

;)

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A beam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. If the electrons have a velocity of 6.5 × 106
defon

Answer:

4.7\cdot 10^{-14}N

Explanation:

For a charge moving perpendicularly to a magnetic field, the force experienced by the charge is given by:

F=qvB

where

q is the magnitude of the charge

v is the velocity

B is the magnetic field strength

In this problem,

q=1.6\cdot 10^{-19} C

v=6.5\cdot 10^6 m/s

B=4.5\cdot 10^{-2} T

So the force experienced by the electrons is

F=(1.6\cdot 10^{-19}C)(6.5\cdot 10^6 m/s)(4.5\cdot 10^{-2} T)=4.7\cdot 10^{-14}N

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1 year ago
Short-range forecasts tends to ________ longer-range forecasts.
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2 years ago
The position of an object is given by x = at3 - bt2 + ct,where a = 4.1 m/s3, b = 2.2 m/s2, c = 1.7 m/s, and x and t are in SI un
Elza [17]

Answer:

The answer to your question is: 15 m/s2

Explanation:

Equation    x = at3 - bt2 + ct

a = 4.1 m/s3

b = 2.2 m/s2

c = 1.7 m/s

First we find  x at t = 4.1 s

x = 4.1(4.1)3 - 2.2(4.1)2 + 1.7(4.1)

x = 4.1(68.921) - 2.2(16.81) + 6.97

x = 282.58 - 36.98 + 6.98

x = 252.58 m

Now we find speed

v = x/t = 252.58/ 4.1 = 61.6 m/s

Finally

acceleration = v/t = 61.6/4.1 = 15 m/s2

6 0
2 years ago
Which best describes what forms in nuclear fission?A. two smaller, more stable nucleiB. two larger, less stable nucleiC. one sma
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Answer:B. two larger, less stable nuclei

Explanation: They collied and don't combine

4 0
2 years ago
Read 2 more answers
An object is 6.0 cm in front of a converging lens with a focal length of 10 cm.Use ray tracing to determine the location of the
Masja [62]

As we know that

\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}

here we know that

d_0 = 6 cm

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Ray diagram is attached below here

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