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Hatshy [7]
2 years ago
7

A 2.00x10^6 hertz radio signal is sent a distance of 7.30x10^10 meters from earth to a spaceship orbiting Mars. How much time do

es it take for the radio signal to travel from earth to the spaceship
Physics
1 answer:
PolarNik [594]2 years ago
5 0

Answer:

It takes  2.43\times 10^2  for the radio signal to travel from earth to the spaceship.

Explanation:

Given:

The frequency of the radio signal =  2.00 \times 10^6 hertz

Distance =7.30\times 10^10 meters

To Find:

The time taken for the radio signal to travel from the earth to the spaceship= ?

Solution:

we know that the time taken can be found by dividing the distance travelled by the speed at which the signal travels

So

Time = \frac{Distance}{Speed}

Here the speed of the radio signal is equal the the speed of light

Now substituting the values,

Time taken is

=>Time = \frac{7.30\times 10^10}{3 \times 10^8}

=>Time = 2.43\times 10^{10-8}

=>Time = 2.43\times 10^2

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1. Si tengo medio kilo de fruta y te doy un cuarto y tú me das tres cuartos de kilo, ¿cuánto tengo? 2. Si en una carrera te qued
Kipish [7]

Answer:

1. Tienes 1 kg de fruta.

2. Queda por recorrer 1/4 km.

3. Ambos pesan lo mismo.

Explanation:

1. Tienes 1/2 kg y cuando te doy 1/4 te queda:

m = \frac{1}{2} - \frac{1}{4} = \frac{1}{4}

Ahora cuando te doy 3/4 kg te queda en total:

m_{T} = \frac{1}{4} + \frac{3}{4} = 1 kg

Por lo tanto, tienes 1 kg de fruta al final.

2. Si falta por recorrer la mitad de la mitad, tenemos:

d = \frac{1/2}{2} = \frac{1}{4}

Entonces, queda por recorrer 1/4 km.

3. El peso (P) del hierro es:

P = m*g    

P = (1 + 1/2)kg*9.81 m/s^{2} = 14.72 N

Y el peso de la paja es:

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Por lo tanto, ambos pesan lo mismo.

Espero que te sea de utilidad!

6 0
2 years ago
A 0.4 kilogram sample of aluminum at 115 degrees Celsius is put into a container containing 0.5 kilograms of water at 15 degrees
AlladinOne [14]

The heat liberated by the aluminium container would be equal to heat absorbed by the water.


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A vehicle has an initial velocity of v0 when a tree falls on the roadway a distance xf in front of the vehicle. The driver has a
Korvikt [17]

Answer:

v^2=v_o^2-2\times a\times (v_o.t)

Explanation:

Given:

Initial velocity of the vehicle, v_o

distance between the car and the tree, x_f

time taken to respond to the situation, t

acceleration of the car after braking, a

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u= initial velocity of the  car when the tree falls

a= acceleration after the brakes are applied

s= distance between the tree and the car after the brakes are applied.

s=v_o\times t

Now for this situation the eq. (1) becomes:

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5 0
2 years ago
What are the two forces that keep a pendulum swinging?
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