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Kruka [31]
2 years ago
5

Two leopards are fighting over a piece of meat they caught while hunting. The leopards pull on the meat muscle with a force of 1

00. N, stretching the 0.10-m-long tendon by 0.0080 m. If the cross-sectional area of the tendon is 1.0 105 m2, what is its stretch modulus?
Physics
1 answer:
kirza4 [7]2 years ago
3 0

Answer:

Stretch Modulus of the given is

Modulus = 1.25 \times 10^8 N/m^2

Explanation:

By the law of elasticity we know that the ratio of stress and strain is known as modulus of elasticity

So here we have

Modulus = \frac{stress}{strain}

here we have

stress = \frac{Force}{Area}

stress = \frac{100}{1.0 \times 10^{-5}}

stress = 10^7 m^2

now similarly we have

strain = \frac{\Delta L}{L}

strain = \frac{0.0080}{0.10}

strain = 0.08

Now we have

Modulus = \frac{10^7}{0.08}

Modulus = 1.25 \times 10^8 N/m^2

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A radioactive substance decays exponentially. A scientist begins with 200 milligrams of a radioactive substance. After 17 hours,
lianna [129]

75.17 mg of the radioactive substance will remain after 24 hours.

Answer:

Explanation:

Any radioactive substance will obey the exponential decay behavior. So according to this behavior, any radioactive substance will be decaying in terms of exponential form of disintegration constant and Time.

Disintegration constant is the rate of decay of radioactive elements. It can be measured using the half life time of the radioactive element .While half life time is the time taken by any radioactive element to decay half of its concentration. Like in this case, at first the scientist took 200 mg then after 17 hours, it got reduced to 100 g. So the half life time of this element is 17 hours.

Then Disintegration constant = 0.6932/Half Life time

Disintegration constant = 0.6932/17=0.041

Then as per the law of disintegration constant:

N = N_{0}e^{-xt}

Here N is the amount of radioactive element remaining at time t and N_{0} is the initial amount of sample, x is the disintegration constant.

So here, N_{0} = 200 mg, x = 0.041 and t = 24 hrs.

N = 200 ×e^{-24*0.041} =75.17 mg.

So 75.17 mg of the radioactive substance will remain after 24 hours.

3 0
2 years ago
The weights of a large number of miniature poodles are approximately normally distributed with a mean of 99 kilograms and a stan
Karo-lina-s [1.5K]

Answer:

See explanation below

Explanation:

As I say in the comments, the question is incomplete, however, I will try to answer this by using data that I found on another site.

This is the part of the question that is not here:

If measurements are recorded to the nearest

tenth of a kilogram, find the fraction of these poodles

with weights

(a) over 9.5 kilograms;

(b) of at most 8.6 kilograms;

So, assuming a mean of 8 kg, and 0.9 of standard deviation, let X represents the weight of the poodles

The expression to calculate the fraction of poodle needed is:

Z = X - u / d

u: weight of the large number of poodle

d: standard deviation

Replacing data of a) wer have:

Z = 9.5 - 8 / 0.9

Z = 1.67

With this value, we need to take the value of Z, and see the area under the curve of standard deviation (see table attached)

Therefore:

P (X > 9.5) = P(Z > 1.67) = 0.5 - P (Z < 1.67) = 0.5 - 0.4525 = 0.0475

b) In this part, is the same as part a) so:

Z = 8.6 - 8 / 0.9 = 0.67

The value for area in the curve is 0.2486 so:

P = 0.5 + 0.2486 = 0.7486

Hope this helps

8 0
2 years ago
Rachel is helping her younger brother replace a broken part in his toy ambulance. This part is responsible for converting electr
Studentka2010 [4]
The light bulb, it takes electrical energy and turns it into l<span>ight energy!</span>
5 0
2 years ago
Read 2 more answers
A 9V battery is directly connected to each of 3 LED bulbs. Select the statement that accurately describes this circuit. A) A dir
Likurg_2 [28]
First off, you can cross out alternating current because a 9V battery doesn't give out AC, it gives out solely DC. If the battery is connected to each battery individually, then they are in parallel. So, according to Kirchhoff's Voltage Law, in parallel, V total = V1 = V2= V3..
So I'd say B) !
7 0
2 years ago
Read 2 more answers
A spring stretches 0.220 m when a 0.400 kg-mass is hung from it. What is its spring constant? (Mass is not a force )
Fantom [35]
We want to know the amount of force that stretches the spring 0.22 m.
That force is the WEIGHT of the mass hung from it.
The weight of the mass is (mass) times (gravity).
To do that calculation, we need to know the value of gravity, but
gravity has different values on every planet.  I shall assume that
this whole springy question is taking place on Earth, so that the
value of gravity is 9.8 m/s² .

The weight of the mass is (0.4 kg) x (9.8 m/s²) = 3.92 Newtons.

The spring constant is

(force/length of the stretch)

= (3.92 Newtons) / (0.22 meters)

= (3.92 / 0.22) Newtons/meter

= 17.82 N/m .

8 0
2 years ago
Read 2 more answers
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