10.67m/s²
32N
Explanation:
Given parameters:
Mass of the body = 3kg
velocity of the mass = 4m/s
radius of circle = 0.75m
Unknown:
centripetal acceleration = ?
centripetal force = ?
Solution:
The centripetal force is the force that keeps a radial body in its circular motion. It is directed inward:
Centripetal acceleration = 
v is the velocity of the body
r is the radius of the circle
putting in the parameters:
Centripetal acceleration = 
Centripetal acceleration = 10.67m/s²
Centripetal force = m
m is the mass
Centripetal force = mass x centripetal acceleration
= 3 x 10.67
= 32N
learn more:
Acceleration brainly.com/question/3820012
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Impulse is equal to change in momentum. So if impulse is 2000 then to solve for new velocity we just set it equal to equation for momentum.
First find original momentum by p=mv
p=1000*20=20000
So then taking that value minus the impulse since it was in opposite direction of original momentum it will slow it down some. To find new velocity we just take
20000-2000=18000=mv
v=18000/1000 =18m/s
Hope this helps!! Any questions please ask!!
Thank you!
ANSWER

EXPLANATION
Since the body is in equilibrium, total upward forces must equal total downward force.
Also the net horizontal forces acting on the body must be zero.
We need to resolve
into vertical and horizontal components.
The horizontal component is
.
The vertical component is
.
Equating the up force to the downward forces gives,
.
This implies that,
.

Also the horizontal forces must be equal.
.
Dividing equation (1) by equation (2) gives,
.


.
Therefore the given angle that
must make with the horizontal is approximately 35° to the nearest degree.
KNOWN: Long, 30mm-diameter cylinder with embedded electrical heater; power required
to maintain a specified surface temperature for water and air flows.
FIND: Convection coefficients for the water and air flow convection processes, hw and ha,
respectively.
ASSUMPTIONS: Flow is cross-wise over cylinder which is very long in the direction
normal to flow.
The convection heat rate from the cylinder per unit length of the cylinder has
the form
q' = h*(pi*D)*(Ts-Tinf)
and solving for the heat transfer convection coefficient, find
Water
hw = q'/((pi*D)*(Ts-Tinf))
hw = (38*10^3 W/m) / ((pi*(0.030m))*(80-25)C)=
7330.77314 W/m^2K
Air
ha = (400W/m) / ((pi*(0.030m))*(80-25)C)=<span>
77.166033 </span> W/m^2K
COMMENTS: Note that the air velocity is 10 times that of the water flow, yet
hw ≈ 95 × ha.
These values for the convection coefficient are typical for forced convection heat transfer with
liquids and gases
Watter is a better convective heat transfer media than air