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2 years ago

A light wave has a 670 nm wavelength in air. Its wavelength in a transparent solid is 420 nm.

Physics

1 answer:

zhuklara [117]2 years ago

4 0

Answer: speed of light in solid = 1.88 * 10^8 m/s

Frequency is constant

Explanation: The relationship between the velocity of light wave and wavelength is given by the formulae below

V = fλ

During refraction, the frequency of light is constant, thus we have that

V = kλ which implies that velocity is proportional to wavelength.

Hence, we have that

v1/ λ1 = v2/ λ2

Where v1 = velocity of light in air = 3 * 10^8 m/s

v2 = velocity of sound in solid

λ1 = wavelength of light in air = 670nm

λ2 = wavelength of light in solid = 420nm

By making v2 subject of formulae, we have that

v2 = v1 * λ2/ λ1

v2 = 3 * 10^8 * 420nm/ 670nm

v2 = 3 * 10^8 * 0.6268

v2 = 1.88 * 10 ^8 m/s

During refraction the frequency of light wave is constant this is because light consist of photons which has energy. it energy needs to be constant and for energy (E=hf) to be constant, frequency would be constant too.

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An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the oc

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The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.

First, we determine how long the parcel will fall using:

s = ut + 1/2 at²

where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity.

5.5 = (0)(t) + 1/2 (9.81)(t)²
t = 1.06 seconds

Now, we may use this time to determine the horizontal distance covered by the parcel by using:
distance = velocity * time

The horizontal velocity of the parcel will be equal to the horizontal velocity of the cruise liner.

Distance = 10 * 1.06
Distance = 10.6 meters

The boat should be 10.6 meters away horizontally from the point of release.

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2 years ago

A man pushes his child in a grocery cart. The total mass of the cart and child is 30.0 kg. If the force resisting the carts moti

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The force applied by the man is 60 N

Explanation:

We can solve this problem by applying Newton's second law, which states that:

$\sum F = ma$ (1)

where

$\sum F$ is the net force acting on the child+cart

m is the mass of the child+cart system

a is their acceleration

In this problem, we have:

m = 30.0 kg is the mass

$a=1.50 m/s^2$

And there are two forces acting on the child+cart system:

The forward force of pushing, F
The force resisting the cart motion, R = 15.0 N

Therefore we can write the net force as

$\sum F = F -R$

where R is negative since its direction is opposite to the motion

So eq.(1) can be rewritten as

$F-R=ma$

And solving for F,

$F=ma+R=(30.0)(1.50)+15.0=60 N$

Learn more about Newton's second law:

brainly.com/question/3820012

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2 years ago

A policeman kicks in a door with a force of 4500 N. What force does the door apply to the policeman’s leg?

Soloha48 [4]

Answer:

-4500 N

Source: Brainly

The police officer must be angry 0_0

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2 years ago

According to Dr. paul Narguizian professor of Biology and Science Education at California State University, ______ are generaliz

Mazyrski [523]

Answer:

I believe the correct answer would be A :)

Explanation:

3 0

1 year ago

A firecracker breaks up into several pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.

MakcuM [25]

Answer:

The magnitude of the total momentum is 21.2 kg m/s and its direction is 39.5° from the x-axis.

Explanation:

Hi there!

The total momentum is calculated as the sum of the momenta of the pieces.

The momentum of each piece is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass.

v = velocity.

The momentum is a vector. The 200 g-piece flies along the x-axis then, its momentum will be:

p = (m · v, 0)

p = (0.200 kg · 82.0 m/s, 0)

p = (16.4 kg m/s, 0)

The 300 g-piece flies along the y-axis. Its momentum vector will be:

p =(0, m · v)

p = (0, 0.300 kg · 45.0 m/s)

p = (0, 13.5 kg m/s)

The total momentum is the sum of each momentum:

Total momentum = (16.4 kg m/s, 0) + (0, 13.5 kg m/s)

Total momentum = (16.4 kg m/s + 0, 0 + 13.5 kg m/s)

Total momentum = (16.4 kg m/s, 13.5 kg m/s)

The magnitude of the total momentum is calculated as follows:

$|p| = \sqrt{(16.4 kgm/s)^2+(13.5 kg m/s)^2}= 21.2 kg m/s$

The direction of the momentum vector is calculated using trigonometry:

cos θ = px/p

Where px is the horizontal component of the total momentum and p is the magnitude of the total momentum.

cos θ = 16.4 kg m/s / 21.2 kg m/s

θ = 39.3 (39.5° if we do not round the magnitude of the total momentum)

Then, the magnitude of the total momentum is 21.2 kg m/s and its direction is 39.5° from the x-axis.

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2 years ago