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2 years ago

6

A spelunker (person who explores caves) determines that the cave entrance is located 349 m, 253° from her current position. How

far south and how far west from her current position is the cave entrance?

1 answer:

adell [148]2 years ago

5 0

You would have to subtract 253 by 349 and you would get 96.

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An object at rest is suddenly broken apart into two fragments by an explosion one fragment acquires twice the kinetic energy of

satela [25.4K]

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1 year ago

A particle has a velocity of v→(t)=5.0ti^+t2j^−2.0t3k^m/s.

Makovka662 [10]

Answer:

a) $a=5 i+2t j - 6\ t^2k$

b) $a=\dfrac{1}{24.83}(5i+4j-24k)\ m/s^2$

Explanation:

Given that

v(t) = 5 t i + t² j - 2 t³ k

We know that acceleration a is given as

$a=\dfrac{dv}{dt}$

$\dfrac{dv}{dt}=5 i+2t j - 6\ t^2k$

$a=5 i+2t j - 6\ t^2k$

Therefore the acceleration function a will be

$a=5 i+2t j - 6\ t^2k$

The acceleration at t = 2 s

a= 5 i + 2 x 2 j - 6 x 2² k m/s²

a=5 i + 4 j -24 k m/s²

The magnitude of the acceleration will be

$a=\sqrt{5^2+4^2+24^2}\ m/s^2$

a= 24.83 m/s²

The direction of the acceleration a is given as

$a=\dfrac{1}{24.83}(5i+4j-24k)\ m/s^2$

a) $a=5 i+2t j - 6\ t^2k$

b) $a=\dfrac{1}{24.83}(5i+4j-24k)\ m/s^2$

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2 years ago

robby skateboards 0.50 blocks to his friend's house in 1.2 minutes. what is his speed? 6.0 blocks/min 6.0 blocks/min, in the dir

Annette [7]

That would be 0.42 blocks per minute

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1 year ago

Read 2 more answers

a 10.0 kg block on a smooth horizontal surface is acted upon by two forces: a horizontal force of 30 N acting to the right and a

Eddi Din [679]

Answer:

$a=-3\ m/s^2$

Explanation:

<u>Second Newton's Law</u>

It allows to compute the acceleration of an object of mass m subject to a net force Fn. The relation is given by

$F_n=m.a$

The net force is the sum of all vector forces applied to the object. The block has two horizontal forces applied (in absence of friction): The 30 N force acting to the right and the 60 N force to the left. The positive horizontal direction is assumed to the right, so the net force is

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Thus, the acceleration can be computed by

$\displaystyle a=\frac{F_n}{m}=\frac{-30}{10}=-3\ m/s^2$

$\boxed{\displaystyle a=-3\ m/s^2}$

The negative sign indicates the block is accelerated to the left

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1 year ago