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Viefleur [7K]
2 years ago
10

An athlete leaves one end of a pool of length l at t = 0 and arrives at the other end at time t1. she swims back and arrives at

the starting position at time t2. if she is swimming initially in the positive x direction, determine her average velocities symbolically in the first half of the swim, the second half of the swim, and the round trip. (assume that time t2 is from the other end of the pool to the starting point. use any variable or symbol stated above as necessary. indicate the direction with the sign of your answer.)
Physics
1 answer:
AysviL [449]2 years ago
5 0

Average velocity is defined as

v = \frac{displacement}{time}

now we have

when she cross the pool in time t1

v = \frac{L}{t_1}

when she cross the pool back to starting position

v = - \frac{L}{t_2}

Here negative sign is for its return path direction which is reversed of its initial direction.

now for the round trip

displacement = 0

so v = 0

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A 0.111 kg hockey puck moving at 55 m/s is caught by a 80. kg goalie at rest. with what speed does the goalie slide on the frict
madreJ [45]

Answer:

0.076 m/s

Explanation:

Momentum is conserved:

m v = (m + M) V

(0.111 kg) (55 m/s) = (0.111 kg + 80. kg) V

V = 0.076 m/s

After catching the puck, the goalie slides at 0.076 m/s.

8 0
2 years ago
During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshi
vladimir2022 [97]

Answer:

At a deceleration of 60g, or 60 times the acceleration due to gravity a person will travel a distance of 0.38 m before coing to a complete stop

Explanation:

The maximum acceleration of the airbag = 60 g, and the duration of the acceleration = 36 ms or 36/1000 s or 0.036 s

To find out how far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60g

we write out the equation of motion thus.

S = ut + 0.5at²

wgere

S = distance to come to complete stop

u = final velocoty = 0 m/s

a = acceleration = 60g = 60 × 9.81

t = time = 36 ms

as can be seen, the above equation calls up the given variable as a function of the required variable thus

S = 0×0.036 + 0.5×60×9.81×0.036² = 0.38 m

At 60g, a person will travel a distance of 0.38 m before coing to a complete stop

7 0
2 years ago
A particle is moving along the x-axis. Its position as a function of time is given as x=bt-ct^2a) What must be the units of the
lisabon 2012 [21]

Answer:

We are given x= bt +ct²

So

A. bxt= m

Because m/s*s= m

So b= m/s and c= m/s²

B.

x= bt-ct²

So at x=0 t=0

x=0 t= 2

We have

bt = ct² so t = b/c at x= 0

So b-2ct= 0

B. To find velocity we use

dx / dt = b - 2 Ct

C. At rest wen V= 0

We have t= b/2c

D. To find acceleration we use

dv / dt = - 2C

3 0
2 years ago
A sharpening wheel is traveling at 5 rad/s, it slows down to rest in 30 seconds while sharpening an axe. What is its angular acc
Ratling [72]

Answer:

Angular acceleration = 0.167 rad/s^2

Explanation:

Given

Initial Angular velocity (w1) = 5 rad/s

Final Angular velocity (w2) = 0 rad/s

Time taken to change velocity from w1 to w2 = 30 seconds

Angular acceleration is equal to the change in angular velocity to the time taken for making thing change

Hence, Angular acceleration

\frac{w_2 -w_1}{t} \\\frac{5-0}{30}\\0.167rad/s^2

3 0
2 years ago
All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is
Digiron [165]
All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is in a state known as constant velocity. The bullet is moving at a constant value of velocity. Acceleration is the rate of velocity so having zero acceleration would mean that there is no change in velocity per unit of time.<span />
8 0
2 years ago
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