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Viefleur [7K]
1 year ago
10

An athlete leaves one end of a pool of length l at t = 0 and arrives at the other end at time t1. she swims back and arrives at

the starting position at time t2. if she is swimming initially in the positive x direction, determine her average velocities symbolically in the first half of the swim, the second half of the swim, and the round trip. (assume that time t2 is from the other end of the pool to the starting point. use any variable or symbol stated above as necessary. indicate the direction with the sign of your answer.)
Physics
1 answer:
AysviL [449]1 year ago
5 0

Average velocity is defined as

v = \frac{displacement}{time}

now we have

when she cross the pool in time t1

v = \frac{L}{t_1}

when she cross the pool back to starting position

v = - \frac{L}{t_2}

Here negative sign is for its return path direction which is reversed of its initial direction.

now for the round trip

displacement = 0

so v = 0

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Answer:

r= 2.17 m

Explanation:

Conceptual Analysis:

The electric field at a distance r from a charge line of infinite length and constant charge per unit length is calculated as follows:

E= 2k*(λ/r) Formula (1)

Where:

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k: Coulomb electric constant. (N*m²/C²)

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Known data

E= 2.9  N/C

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Problem development

We replace data in the formula (1):

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r =( 2*8.99 *10⁹*3.5*10⁻¹⁰) / (2.9)

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Answer:

t = 103.45 n m

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given,

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Formula used in this case

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2.9 \times t =300

t =\dfrac{300}{2.9}

t = 103.45 n m

the minimum thickness of the film of eyedrops t = 103.45 n m

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