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kykrilka [37]
2 years ago
11

Jake uses a fire extinguisher to put out a small fire. When he squeezes the handle, the flame rettardant is released from the ex

tinguisher with considerable force. As a result, Jake has to reinforce his grip on the extinguisher to hold it in place as it pushes back into his hands. The projectile in this scenario is the . The recoil in this scenario is the . The force on the flame rettardant is the force on the extinguisher. The mass of the flame rettardant is the mass of the extinguisher. The acceleration of the flame rettardant is the acceleration of the extinguisher.
Physics
2 answers:
Tpy6a [65]2 years ago
7 0
Can you attach a picture of the actual problem?
pogonyaev2 years ago
5 0

The projectile in this scenario is the flame r.

The recoil in this scenario is the extinguisher.

The force on the flame r is equal to the force on the extinguisher.

The mass of the flame r is less than the mass of the extinguisher.

The acceleration of the flame r is greater than the acceleration of the extinguisher.

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Megan rode the bus to school, which is located 8 kilometers from her home. If Megan's frame of reference is her house, and it to
Dmitriy789 [7]

Answer:

Explanation: idk sry

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2 years ago
A student is collecting the gas given off from a plant in bright sunlight at a temperature of 27°c. The gas being collected is p
Brums [2.3K]

Answer: The gas being collected is probably Oxygen

Explanation:

Plants produce oxygen through a process known as photosynthesis by utilizing carbon monoxide, a by-product produced by humans during the process of breathing. Humans also breathe in the oxygen ( by-product of photosynthesis) produced by the plants. Therefore, humans and plants live in a symbiotic relationship.

Photosynthesis is the process plants use to synthesize food from carbon dioxide and water. Sunlight is used as a energy source. Photosynthesis releases oxygen as a byproduct.

At low temperatures, between 0 and 10 degrees Celsius – the enzymes that carry out photosynthesis do not work efficiently, and this decreases the photosynthetic rate.

At medium temperature above 10 degrees Celsius to below 40 degrees Celsius (e.g 27 degrees Celsius), the photosynthetic enzymes work at their optimum levels, so photosynthesis proceeds.

At a temperature above 40 degrees Celsius, the enzymes that carry out photosynthesis lose their shape and functionality, and the photosynthetic rate declines rapidly.

Equation for photosynthesis reaction:

6CO2 + 6H20 + (energy) = C6H12O6 + 6O2

4 0
2 years ago
Question
nataly862011 [7]

The density of a material is constant and it is given by the ratio of the mass to the volume of the material

The mass of the liquid and the full bottle ae

The mass of the liquid is <u>450 g</u>

The mass of the filled bottle is <u>530 grams</u>

<u></u>

The reason the above values are correct are as follows:

The given parameters are;

Volume of the bottle, V = Half litre

Mass of the bottle, m_b = 80 g

The volume of liquid in the bottle when filled, V = 500 cm³

The density of the olive oil with which the bottle is filled, ρ = 0.9 g/cm³

a. Required:

To calculate the mass of oil in the bottle

Solution:

The volume of oil in the bottle when the bottle is filled, V = 500 cm³

Density, \ \rho = \dfrac{Mass}{Volume}  = \dfrac{m}{V}

The mass of the liquid, m = ρ × V

∴ m = 0.9 g/cm³ × 500 cm³ = 450 g

The mass of the liquid, m = <u>450 g</u>

<u></u>

b. The mass of the oil in the bottle, m = grams

The mass of the full bottle, m_{filled} = m + m_b

∴ m_{filled} = 450 g + 80 g = 530 g

The mass of the full bottle, m_{filled} = <u>530 grams</u>

Learn more about density here:

brainly.com/question/18110802

4 0
1 year ago
A transmission channel is made up of three sections. The first section introduces a loss of 16dB, the second an amplification (o
AlekseyPX

Answer:

P_{out} = 0.100 W = 100 mW

Explanation:

The attached image shows the system expressed in the question.

We can define an expression for the system.

The equivalent equation for the system would be

G_{total} = G_{1} + G_{2} + G_{3}\\G_{total} = -16dB+20dB-10 dB = -6 dB

so, the input signal could be expressed in dB terms

P_{in} [dB] = 10 log_{10}(P_{in}) \\P_{in} [dB] = 10 log_{10}(0.4)\\P_{in} [dB] = -3.97 dB (1)

so the output signal could be expressed as.

P_{out} = P_{in} + G_{1} + G_{2} + G_{3}\\P_{out} = -3.97 dB - 6dB = -9.97 dB

The gain should be expressed in dB terms and power in dBm terms so

P_{out} = -9.97 + 30 = 20.03 dBm

using the (1) equation to find it in terms of Watts

P_{out} = 0.100 W = 100 mW

3 0
2 years ago
A uniformly accelerated car passes three equally spaced traffic signs. The signs are separated by a distance d = 25 m. The car p
DedPeter [7]

Answer:

a) v_{1}=\frac{x_{2}-x_{1}  }{t_{2}-t_{1}  }=\frac{(2(\frac{25}{3})-\frac{25}{3} )m}{3.9s-1.3s}  =3.2051 \frac{m}{s}

b) v_{2}=\frac{x_{3}-x_{2}  }{t_{3}-t_{2}  }=\frac{(25-2(\frac{25}{3}) )m}{5.5s-3.9s}  =5.2083 \frac{m}{s}

c) a=\frac{v_{2}-v_{1}  }{t_{2}-t_{1}  } =\frac{5.2083m/s-3.2051m/s}{5.5s-3.9s} =1.252 \frac{m}{s^{2} }

Explanation:

<em><u>The knowable variables are </u></em>

d_{t}=25m

t_{1}=1.3 s

t_{2}=3.9 s

t_{3}=5.5 s

Since the three traffic signs are <u>equally spaced</u>, the <u>distance between each sign is \frac{25}{3} m</u>

a) v_{1}=\frac{x_{2}-x_{1}  }{t_{2}-t_{1}  }=\frac{(2(\frac{25}{3})-\frac{25}{3} )m}{3.9s-1.3s}  =3.2051 \frac{m}{s}

b) v_{2}=\frac{x_{3}-x_{2}  }{t_{3}-t_{2}  }=\frac{(25-2(\frac{25}{3}) )m}{5.5s-3.9s}  =5.2083 \frac{m}{s}

Since we know the velocity in two points and the time the car takes to pass the traffic signs

c) a=\frac{v_{2}-v_{1}  }{t_{2}-t_{1}  } =\frac{5.2083m/s-3.2051m/s}{5.5s-3.9s} =1.252 \frac{m}{s^{2} }

6 0
1 year ago
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