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kykrilka [37]
2 years ago
11

Jake uses a fire extinguisher to put out a small fire. When he squeezes the handle, the flame rettardant is released from the ex

tinguisher with considerable force. As a result, Jake has to reinforce his grip on the extinguisher to hold it in place as it pushes back into his hands. The projectile in this scenario is the . The recoil in this scenario is the . The force on the flame rettardant is the force on the extinguisher. The mass of the flame rettardant is the mass of the extinguisher. The acceleration of the flame rettardant is the acceleration of the extinguisher.
Physics
2 answers:
Tpy6a [65]2 years ago
7 0
Can you attach a picture of the actual problem?
pogonyaev2 years ago
5 0

The projectile in this scenario is the flame r.

The recoil in this scenario is the extinguisher.

The force on the flame r is equal to the force on the extinguisher.

The mass of the flame r is less than the mass of the extinguisher.

The acceleration of the flame r is greater than the acceleration of the extinguisher.

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Find the net electric force that the two charges would exert on an electron placed at point on the xx-axis at xx = 0.200 mm. Exp
UkoKoshka [18]

Answer:

The question has some details missing, here is the complete question ; A -3.0 nC point charge is at the origin, and a second -5.0nC point charge is on the x-axis at x = 0.800 m. Find the net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 0.200 m.

Explanation:

The application of coulonb's law is used to approach the question as shown in the attached file.

6 0
1 year ago
A series circuit has two 10-ohm bulb is added in a series. Technician A says that the three bulbs will be dimmer than when only
ANTONII [103]

Answer:

Technician  A  is right. The situation will happens even with only two bulbs in series

Explanation:

We must take into account that

1.- All electric device need its nominal voltage to operate

2.-Any and all electric device means an electric load for the source in terms of equation that means any device will implies a drop voltage of V = I*R ( I the flows current and R  the resistance of the device)

3.-Nominal voltage for bulbs are specify for houses voltages you find between fase and neutral wires for instance in Venezuela 120 (v).

4.-In a imaginary circuit of only one bulb, the nominal voltage will be applied and the bulb will operates correctly, but when you add another bulb (in series) the nominal voltage will split  between the two bulbs ( we  could find a situation such as the first bulb work properly but the second one does not). The voltage split according to Ohms law (in such way that the sum of voltage between the terminal of the first bulb plus the voltage at terminals of the second one are equal to nominal voltage.

For that reason all the bulbs are connected in parallel in wich case all of them will operate with the common voltage

4 0
2 years ago
A car drives around a racetrack for 30 seconds. what do you need to know to calculate the average velocity of the car?
boyakko [2]
The time is given, and you want to find the average velocity. To do this, you need to know the distance covered by the driver around the racetrack in that 30 seconds. You divide this by the time, then you will obtain the average velocity in units of, say meters per second.
8 0
1 year ago
Read 2 more answers
Consider the waveform expression. y (x, t) = ym sin (0.333x + 5.36 + 585t) The transverse displacement (y) of a wave is given as
Sonja [21]

Explanation:

The waveform expression is given by :

y(x,t)=y_m\ sin(0.333x+5.36+585t)...........(1)

Where

y is the position

t is the time in seconds

The general waveform equation is given by :

y(x,t)=y_m\ sin(kx+\phi+\omega t)..........(2)

Where

k=\dfrac{2\pi}{\lambda}

\omega=2\pi f

On comparing equation (1) and (2) we get :

0.333=\dfrac{2\pi}{\lambda}

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f = 93.10 Hz

Time period, T=\dfrac{1}{f}

T=\dfrac{1}{0.010}

T = 0.010 s

Phase constant, \phi=5.36\ radian

Hence, this is the required solution.

8 0
2 years ago
Describe the energy transformations that take place when a skier starts skiing down a hill but after a time is brought to rest b
Andrews [41]
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6 0
2 years ago
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