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1 year ago

A 10 kg brick and a 1 kg book are dropped in a vacuum. The force of gravity on the 10 kg brick is what?

2 answers:

7 0

<span>10 times as much. Since F=m*a, and a is constant, the only thing that affects force is the mass.

In response to the below answer, the acceleration due to gravity does not change. The force due to gravity definitely DOES change depending on the mass of the object. Since the force is what the problem asks for, the answer is 10</span>

LuckyWell [14K]1 year ago

3 0

If this is happening on Earth, then the force of gravity between the Earth and the brick is 98 Newtons. It doesn't matter whether the brick is falling, rising, dropped in a vacuum, in water, or into chicken soup, or what else is dropped near it. None of that has any effect on the gravitational force between the Earth and the brick.

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Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

nataly862011 [7]

Answer:

The major ethical issues in leading examination are: an) Informed assent, b) Beneficence-Do not hurt c) Respect for obscurity and secrecy d) Respect for security.

Explanation:

The major ethical issues in leading examination are: an) Informed assent, b) Beneficence-Do not hurt c) Respect for obscurity and secrecy d) Respect for security.

There are a few reasons why it is essential to stick to ethical norms in research. To start with, standards advance the points of exploration, for example, information, truth, and shirking of blunder. For instance, preclusions against creating, adulterating, or distorting research information advance reality and limit mistake.

6 0

1 year ago

Init. A

Gekata [30.6K]

Answer:

v = 1/3 m / s = 0.333 m / s

in the direction of the truck

Explanation:

The average speed is defined by the variation of the position between the time spent

v = Δx / Δt

since the position is a vector we must add using vectors, we will assume that the displacement to the right is positive, the total displacement is

Δx = 20 - 15 +20

Δx = 25 m

therefore we calculate

v = 25/75

v = 1/3 m / s = 0.333 m / s

in the direction of the truck

7 0

1 year ago

Three particles are moving perpendicular to a uniform magnetic field and travel on circular paths (see the drawing). They have t

Vaselesa [24]

Explanation:

Radius of a charged particle is given by

r=mv / Bq

= k/ q

where k = m v / B is a constant.

i.e. more is the magnitude of charge, less is the radius. (inversely proportional)

From the diagram r_3 > r_2 > r_1 (more the curvature, less is the radius)

( although drawing is not given i am assuming the above order, however, one can change the order as per the diagram. The concept used remains the same)

therefore, q_1 > q_2 > q_3 .

7 0

2 years ago

Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley

kenny6666 [7]

Answer:

Hello your question is incomplete attached below is the complete question

Answer : x ( acceleration of mass 4m ) = $\frac{g}{7}$

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

Explanation:

Given data:

mass suspended = 4 meters

mass suspended at other end = 3 meters

first we have to express the kinetic and potential energy equations

The general kinetic energy of the system can be written as

T = $\frac{4m}{2} x^2 + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2$

T = $4mx^2 + 2my^2 -2mxy$

also the general potential energy can be expressed as

U = $-4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant$

The Lagrangian of the problem can now be setup as

$L =4mx^2 +2my^2 -2mxy +2mgy + constant$

next we will take the Euler-Lagrange equation for the generalized equations :

Euler-Lagrange equation = $4x-y =0\\-2y+x +g = 0$

solving the equations simultaneously

x ( acceleration of mass 4m ) = $\frac{g}{7}$

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

8 0

1 year ago

Two billiard balls of equal mass are traveling straight toward each other with the same speed. They meet head-on in an elastic c

Rus_ich [418]

Answer:

0 kg m/s before and after collision

Explanation:

Let m, v be the mass and speed of the 2 balls, respectively, before the collision. Since they have the same mass and same speed but in opposite direction, the total momentum of the system would be:

P = mv - mv = 0 kg m/s

As the collision is elastic. The total momentum after the collision is the same as the total momentum before the collision, which is 0.

5 0

1 year ago