Answer:
75 m
Explanation:
The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.
The horizontal component of the velocity of the projectile is
and it is constant during the motion;
the total time of flight is
t = 5 s
Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:
Answer:395.6 m/s
Explanation:
Given
mass of bullet
mass of wood block
Length of string
Center of mass rises to an height of
initial velocity of bullet
let and
be the velocity of bullet and block after collision
Conserving momentum
-------------1
Now after the collision block rises to an height of 0.38 cm
Conserving Energy for block
kinetic energy of block at bottom=Gain in Potential Energy
substitute the value of in equation 1
a) Average velocity: 2.8 m/s
b) Average velocity: 5.2 m/s
c) Average velocity: 7.6 m/s
Explanation:
a)
The position of the car as a function of time t is given by
where
The average velocity is given by the ratio between the displacement and the time taken:
The position at t = 0 is:
The position at t = 2.00 s is:
So the displacement is
The time interval is
And so, the average velocity in this interval is
b)
The position at t = 0 is:
While the position at t = 4.00 s is:
So the displacement is
The time interval is
So the average velocity here is
c)
The position at t = 2 s is:
While the position at t = 4 s is:
So the displacement is
While the time interval is
So the average velocity is
Learn more about average velocity:
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