An electron is trapped in a square well of unknown width, L. It starts in unknown energy level, n. When it falls to level n-1 it
emits a photon of wavelength λphoton = 2280 nm. When it falls from n-1 to n-2, it emits a photon of wavelength λphoton = 3192 nm.
1) What is the energy of the n to n-1 photon in eV?
En to n-1 =
2) What is the energy of the n-1 to n-2 photon in eV?
En-1 to n-2 =
3) What is the initial value of n?
ninitial =
4) What is the width, L, of the well in nm?
L =
5) What is the longest wavelength of light, λlongest, the well can absorb in nm?
λlongest =
1) What is the energy of the n to n-1 photon in eV?
En to n-1 =
2) What is the energy of the n-1 to n-2 photon in eV?
En-1 to n-2 =
3) What is the initial value of n?
ninitial =
4) What is the width, L, of the well in nm?
L =
5) What is the longest wavelength of light, λlongest, the well can absorb in nm?
λlongest =
1 answer:
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Answer:
275 kPa
Explanation:
mass of the gas=m=1.5 kg
initial volume if the gas=V₁=0.04 m³
initial pressure of the gas= P₁=550 kPa
as the condition is given final volume is double the initial volume
V₂=final volume
V₂=2 V₁
As the temperature is constant
T₁=T₂=T
=
putting the values in the equation.
=
P₂=
P₂=
P₂=275 kPa
So the final pressure of the gas is 275 kPa.
Answer:
28.1 mph
Explanation:
The force of friction acting on the car provides the centripetal force that keeps the car in circular motion around the curve, so we can write:
(1)
where
is the coefficient of friction
m is the mass of the car
g = 9.8 m/s^2 is the acceleration due to gravity
v is the maximum speed of the car
r is the radius of the trajectory
On the snowy day,
So the radius of the curve is
Now we can use this value and re-arrange again the eq. (1) to find the maximum speed of the car on a sunny day, when . We find: