Answer:
Second pit is 375 m deeper compared to first pit.
Explanation:
We have equation of motion s = ut + 0.5at²
First object hits the ground after 5 seconds,
Initial velocity, u = 0 m/s
Acceleration, a = 10 m/s²
Time, t = 5 s
Substituting,
s = ut + 0.5 at²
s = 0 x 5 + 0.5 x 10 x 5²
s = 125 m
Depth of pit 1 = 125 m
Second object hits the ground after 10 seconds,
Initial velocity, u = 0 m/s
Acceleration, a = 10 m/s²
Time, t = 10 s
Substituting,
s = ut + 0.5 at²
s = 0 x 10 + 0.5 x 10 x 10²
s = 500 m
Depth of pit 2 = 500 m
Difference in depths = 500 - 125 = 375 m
Second pit is 375 m deeper compared to first pit.
