The formula for computing the orbital time period of a body is given as:
T² = 4π²r³ / GM
where T is the time period, r is the distance between the two bodies, G is the gravitational constant and M is the mass of the body that is being orbited. If we compute this time using SI units, the working is:
9.58 AU is 1.43 x 10¹² meters
T = √[(4*π²*(1.43 x 10¹²)³) / (6.67 × 10⁻¹¹ * 2 x 10³⁰)]
T = 9.30 x 10⁸ seconds which is approximately 29 years
Using the astronomical units, distance is in astronomical units and the mass is in solar masses. In these conditions, the ratio:
4π²/G = 1 so
T² = a³ (since the solar mass of the sun is 1)
T = √(9.58)³
T = 27 years
Answer:
Rutherford
Explanation:
Basic principles of the Rutherford atomic model.
1. Positively charged particles are in a very small volume compared to the size of the atom.
2. Most of the mass of the atom is in that small central volume. Rutherford did not call it "core" in his initial papal but he did it from 1912.
3. Electrons with negative electrical charge revolve around the nucleus.
4. The electrons rotate at high speeds around the nucleus and in circular paths that it called orbits.
5. Both negatively charged electrons and the positively charged nucleus are held together by an electrostatic attraction force.
Answer:
the wavelength λ of the light when it is traveling in air = 560 nm
the smallest thickness t of the air film = 140 nm
Explanation:
From the question; the path difference is Δx = 2t (since the condition of the phase difference in the maxima and minima gets interchanged)
Now for constructive interference;
Δx= 
replacing ;
Δx = 2t ; we have:
2t = 
Given that thickness t = 700 nm
Then
2× 700 =
--- equation (1)
For thickness t = 980 nm that is next to constructive interference
2× 980 =
----- equation (2)
Equating the difference of equation (2) and equation (1); we have:'
λ = (2 × 980) - ( 2× 700 )
λ = 1960 - 1400
λ = 560 nm
Thus; the wavelength λ of the light when it is traveling in air = 560 nm
b)
For the smallest thickness 
∴ 



Thus, the smallest thickness t of the air film = 140 nm
Answer:
W = 506.75 N
Explanation:
tension = 2300 N
Rider is towed at a constant speed means there no net force acting on the rider.
hence taking all the horizontal force and vertical force in consideration.
net horizontal force:
F cos 30° - T cos 19° = 0
F cos 30° = 2300 × cos 19°
F = 2511.12 N
net vertical force:
F sin 30° - T sin 19°- W = 0
W = F sin 30° - T sin 19°
W = 2511.12 sin 30° - 2300 sin 19°
W = 506.75 N