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riadik2000 [5.3K]
2 years ago
10

2. Heavier football players tend to play on the front line. Why? What law is it?

Physics
2 answers:
Archy [21]2 years ago
5 0

Answer:

Heavier football players are usually on the front line because they have a low point in gravity therefore they are able to block the back running players in a better way. And its Newton's second law.

Explanation:

gogolik [260]2 years ago
4 0

Answer: They are put in front for defense so so they can block the opponents from getting the ball

Explanation:

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A skateboarder travels on a horizontal surface with an initial velocity of 3.2 m/s toward the south and a constant acceleration
Naddika [18.5K]

Answer:

A. 0.432

B. -1.92

C. 1.44 units/second

D. -3.2 units/second

Explanation:

A. To calculate her x position, we just use the following equation of motion to find the distance traveled:

    s=u*t+\frac{1}{2} (a*t^2)

here s = displacement

t = time (in seconds)

a = acceleration

Solving for the distance, we get:

s = 0 * 0.6 + \frac{1}{2}(2.4 * 0.6^2)

s = 0.432 m

Since 0.432 meters east is equals to 0.432 meter in the positive x-direction, the x position is also 0.432.

B. Since the skater has a constant v - velocity of -3.2 m/s, (south means negative y axis), the total distance traveled is:

Distance = speed * time = -3.2 * 0.6 = -1.92 m

The answer is -1.92 units in the y-axis.

C. The x velocity component is the final speed in the east direction, which is going to be:

v^2 - u^2=2*a*s

v^2 = 2*2.4*0.432

v = 1.44 units/second (in positive x direction)

D. Her y velocity component does not change, since the velocity towards the south is a constant 3.2 m/s

Thus the answer is -3.2 units/second in the y-axis.

8 0
2 years ago
Janelle wants to buy some strings of decorative lights for her home. She is trying to decide between two strings of lights that
inysia [295]
If she has a choice and the wiring details are stated on the packaging,
then Janelle should look for lights that are wired in parallel within the
string, and she should avoid lights that are wired in series within the string. 

If a single light in a parallel string fails, then only that one goes out. 
The rest of the lights in the string continue to shimmer and glimmer.

If a single light in a series string fails, then ALL of the lights in that string
go out, and it's a substantial engineering challenge to determine which light
actually failed.
6 0
2 years ago
Read 2 more answers
Points a and b lie in a region where the y-component of the electric field is Ey=α+β/y2. The constants in this expression have t
Drupady [299]

Answer:

V_{a} - V_{b} = 89.3

Explanation:

The electric potential is defined by

         V_{b} - V_{a} = - ∫ E .ds

In this case the electric field is in the direction and the points (ds) are also in the direction and therefore the angle is zero and the scalar product is reduced to the algebraic product.

         V_{b} - V_{a} = - ∫ E ds

We substitute

         V_{b} - V_{a} = - ∫ (α + β/ y²) dy

We integrate

          V_{b} - V_{a} = - α y + β / y

We evaluate between the lower limit A  2 cm = 0.02 m and the upper limit B 3 cm = 0.03 m

           V_{b} - V_{a} = - α (0.03 - 0.02) + β (1 / 0.03 - 1 / 0.02)

            V_{b} - V_{a} = - 600 0.01 + 5 (-16.67) = -6 - 83.33

            V_{b} - V_{a} = - 89.3 V

As they ask us the reverse case

             V_{b} - V_{a} = - V_{b} - V_{a}

             V_{a} - V_{b} = 89.3

3 0
2 years ago
The ends of a massless rope are attached to two stationary objects (e.g., two trees or two cars) so that the rope makes a straig
julia-pushkina [17]

Answer: They are all true

a. The tension in the rope is everywhere the same.

b. The magnitudes of the forces exerted on the two objects by the rope are the same.

c. The forces exerted on the two objects by the rope must be in opposite directions.

d. The forces exerted on the two objects by the rope must be in the direction of the rope.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)  

- Cutiepatutie ☺❀❤

5 0
2 years ago
Which of the following planets helped astronomers locate another planet?
worty [1.4K]

Answer: Pluto,Mercury

Explanation:

6 0
2 years ago
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