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Tamiku [17]
2 years ago
6

An extremely long thin wire carries a uniform linear charge density of 358 nC/m. Find the potential difference between points 5.

0 m and 6.0 m from the wire, provided they are not near either end of the wire. (
Physics
1 answer:
Romashka-Z-Leto [24]2 years ago
7 0

Answer:

1.2kV

Explanation:

We are given that

Linear charge density,\lambda=358nC/m=358\times 10^{-9} C/m

1 nC=10^{-9} C

r_1=5 m

r_2=6 m

We have to find the potential difference between poinst 5.0 m and 6.0 m from the wire.

We know that potential difference of wire

V=2k\lambda ln\frac{r_2}{r_1}

Where

k=9\times 10^9

Substitute the values

V=2\times 9\times 10^9\times 358\times 10^{-9}ln\frac{6}{5}

V=1174.8 V

V=1.17 kV\approx 1.2 kV

1kV=1000 V

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Answer:

Er = 108 [J]

Explanation:

To solve this problem we must understand that the total energy is 200 [J]. Of this energy 44 [J] are lost in sound and 48 [J] are lost in heat. In such a way that these energy values must be subtracted from the total of the kinetic energy.

200 - 44 - 48 = Er

Where:

Er = remaining energy [J]

Er = 108 [J]

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Explanation:

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So...

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When compared to others, how is a greater velocity represented on a motion map?
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Suppose you're on a hot air balloon ride, carrying a buzzer that emits a sound of frequency f. If you accidentally drop the buzz
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Answer:

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Explanation:

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According to Doppler's effect of sound we have

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