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Bumek [7]
1 year ago
14

A lever has a 36cm input arm and a 6cm output arm. find MA.

Physics
1 answer:
Nady [450]1 year ago
6 0

6

Explanation:

The mechanical advantage is a factor that measures how input force increases using a machine.

A lever is a simple machine with the fulcrum at the center.

To calculate the mechanical advantage M.A of levers we use the expression below;

M. A = \frac{F_{b} }{F_{a} } = \frac{a}{b}

F_{a} = input force

F_{b} = output force

a is the distance of the input force from the fulcrum

b is the distance of the output force from the fulcrum

Given

a = 36cm

b = 6cm

M.A = \frac{36cm}{6cm} = 6

learn more:

Torque brainly.com/question/5352966

#learnwithBrainly

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Lucy and her bike together have a mass of 120kg. She slows down from 4.5m/s to 3.5m/s. How much kinetic energy does she lose?
vovangra [49]
The kinetic energy of a moving object is given by
K= \frac{1}{2}mv^2
where m is the object's mass and v its velocity.

In our problem, the initial kinetic energy is:
K_i =  \frac{1}{2} m v_i^2 = \frac{1}{2}(120 kg) (4.5 m/s)^2=1215 J

while the final kinetic energy is:
K_f =  \frac{1}{2}mv_f^2 =  \frac{1}{2}(120 kg)(3.5 m/s)^2= 735 J

So, the kinetic energy lost by Lucy and her bike is
\Delta K = K_i - K_f = 1215 J - 735 J = 480 J
7 0
1 year ago
80 foot-pounds of work is needed to move the sofa in Tyler's apartment. Which of the following statements is true?
erastova [34]
D is the correct answer
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3 0
2 years ago
Two particles collide and stick together. If no external forces act on the two particles, which of the following is correct for
Semmy [17]

Answer:

c.\Delta p=0 and \Delta k

Explanation:

We are given that two particles collide  and stick together.

If there is no external force act on the two particles then ,it is inelastic collision.

Inelastic collision: There is some loss of kinetic energy but the momentum is conserved.

According to law of conservation of momentum

Initial momentum=Final momentum

Change in momentum=Final momentum-Initial momentum=0

Change in momentum=\Delta p=0

Initial kinetic energy is greater than final kinetic energy.

Change in kinetic energy=Final kinetic energy-kinetic energy=- negative

\Delta k

Hence, option c is true.

c.\Delta p=0 and \Delta k

4 0
1 year ago
A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field B⃗ =0.30 Tk^. The normal to t
arlik [135]

Answer:

The magnitude of the torque on the loop due to the magnetic field is 4.7\times10^{-4}\ N-m.

Explanation:

Given that,

Diameter = 10 cm

Current = 0.20 A

Magnetic field = 0.30 T

Unit vectorn=-0.60\hat{i}-0.080\hat{j}

We need to calculate the torque on the loop

Using formula of torque

\tau=NIAB\sin\theta

Where, N = number of turns

A = area

I = current

B = magnetic field

Put the value into the formula

\tau=1\times0.20\times\pi\times(5\times10^{-2})^2\times0.30\times\sin90^{\circ}

\tau=4.7\times10^{-4}\ N-m

Hence, The magnitude of the torque on the loop due to the magnetic field is 4.7\times10^{-4}\ N-m.

5 0
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Evaluate the final kinetic energy of the supply spacecraft for the actual tractor beam force, F(x)=αx3+βF(x)=αx3+β.
Elan Coil [88]

Answer:

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we substitute  and integrate

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in order to finish the calculation we must know the displacement

8 0
1 year ago
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