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Bumek [7]
2 years ago
14

A lever has a 36cm input arm and a 6cm output arm. find MA.

Physics
1 answer:
Nady [450]2 years ago
6 0

6

Explanation:

The mechanical advantage is a factor that measures how input force increases using a machine.

A lever is a simple machine with the fulcrum at the center.

To calculate the mechanical advantage M.A of levers we use the expression below;

M. A = \frac{F_{b} }{F_{a} } = \frac{a}{b}

F_{a} = input force

F_{b} = output force

a is the distance of the input force from the fulcrum

b is the distance of the output force from the fulcrum

Given

a = 36cm

b = 6cm

M.A = \frac{36cm}{6cm} = 6

learn more:

Torque brainly.com/question/5352966

#learnwithBrainly

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A slender rod is 80.0 cm long and has mass 0.370 kg . A small 0.0200-kg sphere is welded to one end of the rod, and a small 0.05
nataly862011 [7]

Answer:

1.10 m/s

Explanation:

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KE=0.5I\omega^{2}

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From the law of conservation of energy, KE=PE hence

0.5I\omega^{2}=mgh where m is mass, I is moment of inertia, \omega is angular velocity, g is acceleration due to gravity and h is height

Substituting m2-m1 for m and 0.5l for h, \frac {2v}{L} for \omega we obtain

0.5I(\frac {2v}{L})^{2}=0.5Lg(m2-m1)

(\frac {2v}{L})^{2}=\frac {gl(m2-m1)}{I} and making v the subject

v^{2}=\frac {gl^{3}(m2-m1)}{4I}

v=\sqrt {\frac {gl^{3}(m2-m1)}{4I}}

For the rod, moment of inertia I=\frac {ML^{2}}{12} and for sphere I=MR^{2} hence substituting 0.5L for R then I=M(0.5L)^{2}

For the sphere on the left hand side, moment of inertia I

I=m1(0.5L)^{2} while for the sphere on right hand side, I=m2(0.5L)^{2}

The total moment of inertia is therefore given by adding

I=\frac {ML^{2}}{12}+ m1(0.5L)^{2}+ m2(0.5L)^{2}=\frac {L^{2}(M+3m1+3m2)}{12}

Substituting \frac {L^{2}(M+3m1+3m2)}{12} for I in the equation v=\sqrt {\frac {gL^{3}(m2-m1)}{4I}}

Then we obtain

v=\sqrt {\frac {gL^{3}(m2-m1)}{4(\frac {L^{2}(M+3m1+3m2)}{12})}}=\sqrt {\frac {3gL^{3}(m2-m1)}{L^{2}(M+3m1+3m2)}}

This is the expression of linear speed. Substituting values given we get

v=\sqrt {\frac {3*9.81*0.8^{3}(0.05-0.02)}{0.8^{2}(0.39+3(0.02)+3(0.05))}} \approx 1.08 m/s

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2 years ago
A bullet blasts from the barrel of a gun upward in the vertical direction with an initial speed of 700 m/s . Find the maximum al
ryzh [129]

The maximum altitude that the bullet will reach is the point at which its velocity is zero. The equation that may be used in order to determine the altitude is,

<span>                                   D = ((Vi)2 – (Vf)2)/2g</span>

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Substituting the known values,

<span>                                    D = ((700 m/s)2 – (0 m/s)2) / (2(-9.8 m/s2))</span>

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Thus, the maximum height is 25000 m.

 

For the time needed to reach it, we use the equation,

<span>                                    Vf = Vi – (g)(t)</span>

Substituting,

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<span> </span>

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2 years ago
An iron ball and an aluminum ball of mass 100 g each are heated to the same temperature and then cooled to a temperature of 20°C
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As the temperature changes and their masses are the same, heat lost by the balls is directly proportional to their specific heat values. The heat lost by the aluminum ball is higher implies aluminum has higher specific heat.
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Compare the components that make up the windsurfer, his board, and his surroundings.
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Answer:

Sample Response: The windsurfer, his board, and the air and water around him are all made of matter. That matter is made up of very small particles called atoms.

Explanation:

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A charge of uniform volume density (40 nC/m3) fills a cube with 8.0-cm edges. What is the total electric flux through the surfac
GREYUIT [131]

Answer:

The flux through the surface of the cube is 2.314\ Nm^{2}/C

Solution:

As per the question:

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Now,

To calculate the electric flux:

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\phi = electric flux

\epsilon_{o} = 8.85\times 10^{- 12}\ F/m = permittivity of free space  

Volume Charge density for the given case is given by the formula:

\rho_{v} = \frac{Total\ charge, q}{Volume of cube, V}                  (2)

Volume of cube, V = a^{3}

Thus

V = (8.0\times 10^{- 2})^{3} = 5.12\times 10^{- 4}\ m^{3}

Thus from eqn (2), the total charge is given by:

q = \rho_{v}V = 40\times {- 9}\times 5.12\times 10^{- 4}

q = 2.048\times 10^{-11}\ F = 20.48\ pF

Now, substitute the value of 'q' in eqn (1):

\phi = \frac{2.048\times 10^{-11}}{8.85\times 10^{- 12}} = 2.314\ Nm^{2}/C

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2 years ago
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