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Nadusha1986 [10]

2 years ago

10

Which title best reflects the main idea of the passage? The Role of Convection in the Distribution of Earth's Energy The Role of

Heat Transfer Methods in the Distribution of Earth's Energy Conduction, Convection, and Radiation: Methods of Heat Transfer Conduction, Convection, and Radiation: The Heating Up of Earth's Surface

2 answers:

Leto [7]2 years ago

8 0

Answer:

The Role of Heat Transfer Methods in the Distribution of Earth's Energy

Explanation:

oee [108]2 years ago

5 0

Answer:

Convection

Explanation:

It is the currents of the hot gooey mantel of one of the layers of the earth

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A truck traveling at a constant speed of 40.0 km/h applies its brakes and comes to a complete stop in 5.0 s.

I am Lyosha [343]

Answer:

Part a)

$v = 11.11 m/s$

Part c)

$a = -2.22 m/s^2$

This mean the truck is decelerating and its speed is decreasing

Part e)

$t = 13.89 s$

Part f)

$d = 77.14 m$

Explanation:

Part a)

Speed of the truck is given as

$v = 40 km/h$

as we know that

1 km = 1000 m

1 h = 3600 s

so we will have

$v =40 \times \frac{1000}{3600} m/s$

$v = 11.11 m/s$

Part c)

Average acceleration is given as

$a = \frac{v_f - v_i}{t}$

now we have

$a = \frac{0 - 11.11}{5}$

$a = -2.22 m/s^2$

Part e)

as we know that it is uniform acceleration

so we can say

$v_f - v_i = at$

$11.11 - 0 = 0.80 t$

$t = 13.89 s$

Part f)

distance traveled by the truck is given as

$d = \frac{1}{2}at^2$

$d = \frac{1}{2}(0.80)(13.89^2)$

$d = 77.14 m$

4 0

2 years ago

Read 2 more answers

Two tiny particles having charges 20.0 μC and 8.00 μC are separated by a distance of 20.0 cm What are the magnitude and directio

Alecsey [184]

Answer:

The magnitude and direction of electric field midway between these two charges is $10.8\times10^{5}\ N/C$ along AB.

Explanation:

Given that,

First charge $q_{1}= 20\mu C$

second charge $q_{2}= 8\mu C$

Distance = 20 cm

We need to calculate the electric field

For first charge,

Using formula of electric field

$E_{1}= \dfrac{kq_{1}}{r^2}$

Put the valueinto the formula

$E_{1}=\dfrac{9\times10^{9}\times20\times10^{-6}}{10\times10^{-2}}$

$E_{1}=18\times10^{5}\ N/C$

Direction of electric field along AB

We need to calculate the electric field

For second charge,

Using formula of electric field

$E_{2}= \dfrac{kq_{2}}{r^2}$

Put the valueinto the formula

$E_{2}=\dfrac{9\times10^{9}\times8\times10^{-6}}{10\times10^{-2}}$

$E_{2}=7.2\times10^{5}\ N/C$

Direction of electric field along AO

We need to calculate the net electric field at midpoint

$E_{net}=E_{1}-E_{2}$

$E_{net}=(18-7.2)\times10^{5}\ N/C$

$E_{net}=10.8\times10^{5}\ N/C$

Direction of net electric field along AB

Hence, The magnitude and direction of electric field midway between these two charges is $10.8\times10^{5}\ N/C$ along AB.

8 0

2 years ago

The data table below shows the distribution of the energies of a pendulum 0.60 s into its motion. What is the missing value?

ohaa [14]

The total energy (also called mechanical energy) is the sum of the kinetic energy and potential energy:
$TE = KE + PE$
For this pendulum, we see that at t=0.60 s the total energy is TE=0.918 J while the potential energy is 0.054 J, so the kinetic energy (the missing value in the table) is
$KE=TE-PE=0.918 J - 0.054 J =0.864 J$

4 0

2 years ago

An infinite conducting cylindrical shell of outer radius r1 = 0.10 m and inner radius r2 = 0.08 m initially carries a surface ch

gayaneshka [121]

Answer:

Explanation:

Solution is in the picture attached

8 0

2 years ago

For a particular reaction, the change in enthalpy is 51kJmole and the activation energy is 109kJmole. Which of the following cou

Ronch [10]

Answer

given,

change in enthalpy = 51 kJ/mole

change in activation energy = 109 kJ/mole

when a reaction is catalysed change in enthalpy between the product and the reactant does not change it remain constant.

where as activation energy of the product and the reactant decreases.

example:

ΔH = 51 kJ/mole

E_a= 83 kJ/mole

here activation energy decrease whereas change in enthalpy remains same.

5 0

2 years ago