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Karo-lina-s [1.5K]
2 years ago
5

To navigate, a porpoise emits a sound wave that has a wavelength of 2.2 cm. The speed at which the wave travels in seawater is 1

522 m/s. Find the period of the wave.
Physics
1 answer:
Alenkasestr [34]2 years ago
3 0

To solve this problem we will apply the concept related to frequency, by which it is defined as the relationship between the speed of the wave and the wavelength. Since the frequency is the inverse of the period, this relationship will also be reversed. That is to say,

f = \frac{v}{\lambda}

Here,

v = Velocity

\lambda = Wavelength

Now the period is defined as,

T = \frac{1}{f}

Therefore

T = \frac{\lambda}{v}

Replacing we have that,

T = \frac{2.2*10^{-2}}{1522}

T = 1.445*10^{-5}s

Therefore the period of the wave is 1.445*10^{-5}s

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An ice rescue team pulls a stranded hiker off a frozen lake by throwing him a rope and pulling him horizontally across the essen
Anuta_ua [19.1K]

Answer:T=116.84 N

Explanation:

Given

Weight of hiker =1040 N

acceleration a=1.1 m/s^2

Force exerted by Rope is equal to Tension in the rope

F_{net}=T=ma_{net}

T=\frac{1040}{g}\times 1.1

T=116.84 N

8 0
2 years ago
(b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her av
svet-max [94.6K]

Answer:

The time taken is missing in the question. The time is 18 minutes.

The answer is 34.3 km/hr

Explanation:

Average velocity is the speed or the velocity which is required to cover a distance in a time interval.

The time taken is = 18 min

                            = 18/60 hours

The distance from the university to her home is = 10.3 km

Therefore, the average velocity is = displacement/time taken

                                                         = 10.3 / (18/60) km/hr

                                                         = 34.3 km/hr

Hence, the average velocity is 34.3 km/hr

7 0
2 years ago
Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. The heat capacity of Object A is
Oksi-84 [34.3K]

Answer:

Explanation:

Heat capacity A = 3 x heat capacity of B

initial temperature of A = 2 x initial temperature of B

TA = 2 TB

Let T be the final temperature of the system

Heat lost by A is equal to the heat gained by B

mass of A x specific heat of A x (TA - T) = mass of B x specific heat of B x ( T - TB)

heat capacity of A x ( TA - T) = heat capacity of B x ( T - TB)

3 x heat capacity of B x ( TA - T) = heat capacity of B x ( T - TB)

3 TA - 3 T = T - TB

6 TB + TB = 4 T

T = 1.75 TB

8 0
2 years ago
4. Susan observed that different kinds and amounts of fossils were present in a cliff behind her house. She wondered why changes
posledela
5,10,15,20,25,30, that's how much it should have been
3 0
2 years ago
Read 2 more answers
A majorette in a parade is performing some acrobatic twirlings of her baton. Assume that the baton is a uniform rod of mass 0.12
den301095 [7]

Question

Initially, the baton is spinning about a line through its center at angular velocity 3.00 rad/s.  What is its angular momentum? Express your answer in kilogram meters squared per second.

Answer:

0.0192 kgm^{2}/s

Explanation:

The angular momentum L of the baton moving about an axis perpendicular to it, passing through the center of the baton is,

L = \frac{1}{{12}}m{l^2}\omega

Here, l is the length of the baton.

Substitute 0.120 kg for m, 3 rads/s for \omega[\tex] and 0.8 m for l [tex]\begin{array}{c}\\L = \frac{1}{{12}}m{l^2}\omega \\\\ = \frac{1}{{12}}\left( {0.120{\rm{ kg}}} \right){\left( {{\rm{80}}{\rm{.0 cm}}} \right)^2}{\left( {\frac{{1 \times {{10}^{ - 2}}{\rm{m}}}}{{1{\rm{ cm}}}}} \right)^2}\left( {{\rm{3}}{\rm{.00 rad/s}}} \right)\\\\ = 0.0192{\rm{ kg}} \cdot {{\rm{m}}^{\rm{2}}}{\rm{/s}}\\\end{array}

5 0
2 years ago
Read 2 more answers
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