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Karo-lina-s [1.5K]

2 years ago

5

To navigate, a porpoise emits a sound wave that has a wavelength of 2.2 cm. The speed at which the wave travels in seawater is 1

522 m/s. Find the period of the wave.

1 answer:

Alenkasestr [34]2 years ago

3 0

To solve this problem we will apply the concept related to frequency, by which it is defined as the relationship between the speed of the wave and the wavelength. Since the frequency is the inverse of the period, this relationship will also be reversed. That is to say,

$f = \frac{v}{\lambda}$

Here,

v = Velocity

$\lambda$ = Wavelength

Now the period is defined as,

$T = \frac{1}{f}$

Therefore

$T = \frac{\lambda}{v}$

Replacing we have that,

$T = \frac{2.2*10^{-2}}{1522}$

$T = 1.445*10^{-5}s$

Therefore the period of the wave is $1.445*10^{-5}s$

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A 0.0427 kg racquet-ball is moving

Gwar [14]

Answer:

Mass of the box = 0.9433 kg

Explanation:

Mass of racket-ball $(m_1)$ = 0.00427 kg

Velocity of racket-ball before collision $(v_{1i})$ = 22.3 m/s

Velocity of racket-ball after collision with box $(v_{1f})$ = -11.5 m/s

[Since ball is bouncing back, so velocity is taken negative.]

Velocity of the box before collision $v_{2i}$ = 0 m/s

<em>[Since the box is stationary, so velocity is taken zero]</em>

Velocity of box moving forward after collision $v_{2f}$ = 1.53 m/s

To find the mas of the box $m_2$ .

By law of conservation of momentum we have:

Momentum before collision = Momentum after collision

This can be written as:

$p_i=p_f$

$m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}$

We can plugin the given value to find $m_2$

$(0.0427\times 22.3)+(m_2\times 0)=(0.0427\times (-11.5))(m_2\times 1.53)$

$0.9522+0=-0.4911+1.53m_2$

Adding both sides by 0.4911

$0.9522+0.4911=-0.4911+0.4911+1.53m_2$

$1.4433=1.53m_2$

Dividing both sides by 1.53.

$\frac{1.4433}{1.53}=\frac{1.53m_2}{1.53}$

$0.9433=m_2$

∴ $m_2=0.9433$ kg

Mass of the box = 0.9433 kg (Answer)

4 0

2 years ago

A 6.0-Ï‰ and a 12-Ï‰ resistor are connected in parallel across an ideal 36-v battery. What power is dissipated by the 6.0-Ï‰ res

Elena L [17]

Answer:

P = 216 Watts

Explanation:

Given that,

Resistance 1, $R_1=6\ \Omega$

Resistance 2, $R_2=12\ \Omega$

Voltage, V = 36 V

We need to find the power dissipated by the 6 ohms resistor. In case of parallel circuit, voltage throughout the circuit is same while the current is different.

Firstly, lets find current of the 6 ohms resistor such that,

V = IR

$I=\dfrac{V}{R}\\\\I=\dfrac{36}{6}\\\\I=6\ A$

The power dissipated by 6 ohms resistor is given by :

$P=I^2R$

$P=6^2\times 6\\\\P=216\ W$

So, the power dissipated across 6 ohm resistor is 126 watts.

8 0

2 years ago

When a 85 kg man sits on the stool, by what percent does the length of the legs decrease? assume, for simplicity, that the stool

BabaBlast [244]

Find stress using the formula Stress = Force / Area. Here, force exerted by 85kg person on stool is F = mg = 85kg * 9.8 m/s^2 = 833N. Find total area of 3 legs A = 3 π (D/2)^2 = 3 π (2.5 x 10^-2 / 2)^2 = 1.4726 x 10^-3 m^2. Now substitute in Stress = Force/Area. Stress = 833N / 1.4726 x 10^-3 m^2 = 5.656 x 10^5 N/m^2. Find strain using the formula strain = Stress / Young’s modulus. For wood, Y = 1.3 x 10^10 N/m^2. Thus, strain = 5.656x10^5 N/m^2 / 1.3x10^10 N/m^2 = 4.35 x 10^-5 = 0.00435%.

Therefore, the legs decrease by 0.00435%

7 0

2 years ago

A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your ans

Anna71 [15]

The Gravitationa potential energy of the mass (PEG) is given by:
$U=mgh$
where
m is the mass
g is the gravitational acceleration
h is the heigth of the mass above the reference level (the ground)

In this problem, $m=250 kg$ and $h=0.5 m$ , therefore the gravitational potential energy of the mass is:
$U=mgh=(250 kg)(9.8 m/s^2)(0.5 m)=1225 J$

6 0

2 years ago

Read 2 more answers

You slide a coin across the floor, and observe that it slows down and eventually stops. A sensitive thermometer shows that its t

dolphi86 [110]

Answer:

Explanation:

Coin slide across the floor and finally comes to stop with an increase in temperature.

We can conclude that the coin interacted with one or more object which reduces its velocity.

It is also possible that coin stop due to friction which elevates the coin temperature by converting some part of its energy into thermal energy

6 0

2 years ago