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Harlamova29_29 [7]
1 year ago
11

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1

+ F/m where a1 = 3.00 meter/ second2 F=12.0 kilogram.meter/second2 and m=7.00 kilogram. First which of the following is the correct step for obtaining a common denominator for the two fractions in the expression in solving for a?a. (m/m times a1/1) + (1/1 times F/m)b. (1/m times a1/1) + (1/m times F/m)c. (m/m times a1/1) + (F/F times F/m)d. (m/m times a1/1) +(m/m times F/m )
Physics
1 answer:
AlekseyPX1 year ago
8 0

Explanation:

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression :

a=a_1+\dfrac{F}{m}

Where

a_1=3\ m/s^2

F=12\ kg-m/s^2

m = 7 kg

So, the correct step for obtaining a common denominator for the two fractions in the expression in solving for a is (a) and the value of a is :

a=3+\dfrac{12}{7}

a=4.71\ m/s^2

Hence, the correct option is (a).

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Answer:

The magnitude of the acceleration of the car is 35.53 m/s²

Explanation:

Given;

acceleration of the truck, a_t = 12.7 m/s²

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mass of the car, m_c = 890 kg

let the acceleration of the car at the moment they collided = a_c

Apply Newton's third law of motion;

Magnitude of force exerted by the truck = Magnitude of force exerted by the car.

The force exerted by the car occurs in the opposite direction.

F_c = -F_t\\\\m_ca_c = -m_t a_t\\\\a_c =- \frac{m_ta_t}{m_c} \\\\a_c = -\frac{2490 \times 12.7}{890} \\\\a_c = - 35.53 \ m/s^2

Therefore, the magnitude of the acceleration of the car is 35.53 m/s²

3 0
2 years ago
You want to examine the hairy details of your favorite pet caterpillar, using a lens of focal length 8.9 cm 8.9 cm that you just
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Answer:

The angular magnification is M = 2.808

Explanation:

From the question we are told

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The angular magnification is mathematically represented as

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Substituting values

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4 0
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Answer:

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According to my research on different architectural engineering techniques, I can say that based on the information provided within the question this is an example of choosing a material that will show warning before it fails. By choosing aluminum he can detect certain failures a long time before it actually happens since aluminum shows signs of wear and tear and doesn't just break immediately.

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