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Harlamova29_29 [7]
1 year ago
11

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1

+ F/m where a1 = 3.00 meter/ second2 F=12.0 kilogram.meter/second2 and m=7.00 kilogram. First which of the following is the correct step for obtaining a common denominator for the two fractions in the expression in solving for a?a. (m/m times a1/1) + (1/1 times F/m)b. (1/m times a1/1) + (1/m times F/m)c. (m/m times a1/1) + (F/F times F/m)d. (m/m times a1/1) +(m/m times F/m )
Physics
1 answer:
AlekseyPX1 year ago
8 0

Explanation:

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression :

a=a_1+\dfrac{F}{m}

Where

a_1=3\ m/s^2

F=12\ kg-m/s^2

m = 7 kg

So, the correct step for obtaining a common denominator for the two fractions in the expression in solving for a is (a) and the value of a is :

a=3+\dfrac{12}{7}

a=4.71\ m/s^2

Hence, the correct option is (a).

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Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th
Stels [109]

This question deals with the law of conservation of momentum, which basically says that the total momentum in a system must stay the same, provided there are no outside forces. Since you were given the mass and velocity of the two objects you can find the momentum (p=mv) of each and then add them together to find the total momentum of the system before they collide. This total momentum must be the same after they collide.  Since you have the mass and velocity of one of the objects after the collision you can find the its momentum after.  Subtract this from the the system total and you will have the momentum of the other object after the collision.  Now that you know the momentum of the other object you can find its velocity using p=mv and its mass from before.

Be careful with the velocities.  They are vectors, so direction matters.  Typically moving to the right is positive (+) and moving to the left is negative (-).  It is not clear from your question which direction the objects are moving before and after the collision.

6 0
1 year ago
Read 2 more answers
How much is the moment due to force P about point B. P(unit=N) vector is equal to (150i+260j ) and vector BA (unit=meter) is equ
artcher [175]

Answer:

The moment (torque) is given by the following equation:

\vec{\tau} = \vec{r} \times \vec{F}\\\vec{r} \times \vec{F} = \left[\begin{array}{ccc}\^{i}&\^j&\^k\\r_x&r_y&r_z\\F_x&F_y&F_z\end{array}\right] = \left[\begin{array}{ccc}\^{i}&\^j&\3k\\0.23&0.04&0\\150&260&0\end{array}\right] = \^k((0.23*260) - (0.04*150)) = \^k (53.8~Nm)

Explanation:

The cross-product between the distance and the force can be calculated using the method of determinant. Since the z-components are zero, it is easy to calculate.

4 0
1 year ago
At what height h above the ground does the projectile have a speed of 0.5v?
maw [93]

Answer:

h=\dfrac{3v^2}{8g}

Explanation:

It is given that,

Speed of the projectile is 0.5 v. Let h is the height above the ground. Using the first equation of motion to find it.

v=u+at

v=u-gt

Initial speed of the projectile is v and final speed is 0.5 v.

0.5v=v-gt

t=\dfrac{v}{2g}

g is the acceleration due to gravity

Let h is the height above the ground. Using the second equation of motion as :

h=vt-\dfrac{1}{2}gt^2

h=v\dfrac{v}{2g}-\dfrac{1}{2}g(\dfrac{v}{2g})^2

h=\dfrac{3v^2}{8g}

So, the height of the projectile above the ground is \dfrac{3v^2}{8g}. Hence, this is the required solution.

6 0
1 year ago
a hippopotamus produces a pressure of 250000 pa when it is standing on all four feet if the weight of the hippo is 40000 N what
mamaluj [8]

0.04m²

Explanation:

Given parameters:

Pressure = 250000Pa

Weight = 40000N

Unknown:

Area of each foot = ?

Solution:

Pressure is the force exerted per unit area of a body

  Pressure = \frac{force}{area}

To find the area;

        Area = \frac{force }{pressure}

    Area = \frac{40000}{250000} = 0.16m²

The force exerted by all the four feet is 0.16m²

the area of each feet = \frac{0.16}{4} = 0.04m²

Learn more:

Pressure brainly.com/question/7139767

#learnwithBrainly

8 0
1 year ago
What is the electric potential vtot at the center of the square? make the usual assumption that the potential tends to zero far
Romashka-Z-Leto [24]
Missing figure of the problem: http://tsephysics.weebly.com/uploads/5/1/9/3/51934203/477140_orig.jpg

Solution:
Assuming the potential is zero at infinite distance from the charge, then the potential at a certain distance r from a single point charge is 
V(r)=k_e  \frac{q}{r}
where k_e=8.99\cdot 10^9 Nm^2C^{-2} is the Coulomb's constant.

In our problem, we just have to superimpose the potential generated by every charge. The diagonal of the square is \sqrt{2} d, therefore the distance between each charge and the center of the square is \frac{ \sqrt{2} }{2} d.
So, the total potential is:
V=V_1+V_2+V_3+V_4=
=k_e \frac{q}{ \frac{ \sqrt{2}d }{2} }+ k_e \frac{2q}{ \frac{ \sqrt{2}d }{2} }+k_e \frac{5q}{ \frac{ \sqrt{2}d }{2} }-k_e \frac{3q}{ \frac{ \sqrt{2}d }{2} }=
=5 \sqrt{2} k_e  \frac{q}{d}
7 0
2 years ago
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