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Harlamova29_29 [7]
1 year ago
11

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1

+ F/m where a1 = 3.00 meter/ second2 F=12.0 kilogram.meter/second2 and m=7.00 kilogram. First which of the following is the correct step for obtaining a common denominator for the two fractions in the expression in solving for a?a. (m/m times a1/1) + (1/1 times F/m)b. (1/m times a1/1) + (1/m times F/m)c. (m/m times a1/1) + (F/F times F/m)d. (m/m times a1/1) +(m/m times F/m )
Physics
1 answer:
AlekseyPX1 year ago
8 0

Explanation:

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression :

a=a_1+\dfrac{F}{m}

Where

a_1=3\ m/s^2

F=12\ kg-m/s^2

m = 7 kg

So, the correct step for obtaining a common denominator for the two fractions in the expression in solving for a is (a) and the value of a is :

a=3+\dfrac{12}{7}

a=4.71\ m/s^2

Hence, the correct option is (a).

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A coffee cup on the horizontal dashboard of a car slides forward when the driver decelerates from 45 kmh to rest in 3.5 s or les
Svetach [21]

Answer:

μs = 0.36

Explanation:

Assuming no other forces acting on the cup while the car is decelerating, the friction force is responsible for any horizontal movement of the cup.

If the cup is on the verge of starting to slide, the friction force can be expressed as follows:

Ff = -μs*N = -μs*m*g

This force produces a deceleration from 45 Kmh to rest, in 3.5 s or  more.

Converting 45 kmh to m/s, we have:

45 kmh *\frac{1000m}{1km} * \frac{1h}{3600 s} = 12.5 m/s

We can find the acceleration, just applying the definition, with vf =0, as follows:

a = \frac{-vf}{t} =\frac{-12.5m/s}{3.5s} = -3.57 m/s2

According to Newton's 2nd law, we can write the following expression:

F = m*a = -μs*m*g

Simplifying common terms, we can solve for μs, as follows:

μs = \frac{a}{-g} =\frac{-3.57 m/s2}{-9.80m/s2} = 0.36

6 0
2 years ago
Sasha is ordered Ampicillin 50mg/kg/day x 48 hours, to be given every 6 hours in 100mls of N/S run over 30 minutes. The tubing h
Anna007 [38]

Answer:

The correct dose = 1454.54 mg

and The jnfusion rate = 41.67 gitt/hr

Explanation: the correct dose will be 50mg/kg × kg/2.2 × 64lb

= 1454.54 mg

infusion rate will be

10 gtts/ml × 50mg/6 × 30/60

Infusion rate = 15000/360

= 41.67 gitt/hr

5 0
2 years ago
Write the equivalent formulas for velocity, acceleration, and force using the relationships covered for UCM, Newton’s Laws, and
yKpoI14uk [10]

Answer:

The newton’s second law is F=ma

The Gravitational force is F=\dfrac{Gm_{1}m_{2}}{r^2}

Explanation:

Given that,

The equivalent formulas for velocity, acceleration, and force using the relationships covered for UCM, Newton’s Laws, and Gravitation.

We know that,

Velocity :

The velocity is equal to the rate of position of the object.

v=\dfrac{dx}{dt}....(I)

Acceleration :

The acceleration is equal to the rate of velocity of the object.

a=\dfrac{dv}{dt}....(II)

Newton’s second Laws

The force is equal to the change in momentum.

In mathematically,

F=\dfrac{d(p)}{dt}

Put the value of p

F=\dfrac{d(mv)}{dt}

F=m\dfrac{dv}{dt}

Put the value from equation (II)

F=ma

This is newton’s second laws.

Gravitational force :

The force is equal to the product of mass of objects and divided by square of distance.

In mathematically,

F=\dfrac{Gm_{1}m_{2}}{r^2}

Where, m₁₂ = mass of first object

m= mass of second object

r = distance between both objects

Hence, The newton’s second law is F=ma

The Gravitational force is F=\dfrac{Gm_{1}m_{2}}{r^2}

3 0
2 years ago
Paintball guns were originally developed to mark trees for logging. A forester aims his gun directly at a knothole in a tree tha
emmasim [6.3K]

Answer:

The distance between knothole and the paint ball is 0.483 m.

Explanation:

Given that,

Height = 4.0 m

Distance = 15 m

Speed = 50 m/s

The angle at which the forester aims his gun are,

\tan\theta=\dfrac{4}{15}

\tan\theta=0.266

\cos\theta=\dfrac{15}{\sqrt{15^2+4^2}}

\cos\theta=0.966

Using the equation of motion of the trajectory

The horizontal displacement of the paint ball is

x=(u\cos\theta)t

t=\dfrac{x}{u\cos\theta}

Using the equation of motion of the trajectory

The vertical displacement of the paint ball is

y=u\sin\theta(t)-\dfrac{1}{2}gt^2

y=u\sin\theta(\dfrac{x}{u\cos\theta})-\dfrac{1}{2}g(\dfrac{x}{u\cos\theta})^2

y=x\tan\theta-\dfrac{gx^3}{2u^2(\cos\theta)^2}

Put the value into the formula

y=(15\times0.266)-(\dfrac{9.8\times(15)^2}{2\times(50)^2\times(0.966)^2})

y=3.517\ m

We need to calculate the distance between knothole and the paint ball

d=h-y

d=4-3.517

d=0.483\ m

Hence, The distance between knothole and the paint ball is 0.483 m.

8 0
2 years ago
The cockroach Periplaneta americana can detect a static electric field of magnitude 8.50 kN/C using their long antennae. If the
otez555 [7]

Answer:

0.647 nC

Explanation:

The force experienced by a charge due to the presence of an electric field is given by

F=qE

where

q is the charge

E is the magnitude of the electric field

In this problem, each antenna is modelled as it was a single point charge, experiencing a force of

F=5.50\mu N = 5.50\cdot 10^{-6} N

Therefore, if the electric field magnitude is

E=8.50 kN/C = 8500 N/C

Then the charge on each antenna would be

q=\frac{F}{E}=\frac{5.50\cdot 10^{-6} N}{8500 N/C}=6.47\cdot 10^{-10} C = 0.647 nC

8 0
2 years ago
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