Answer:
3 hours
Explanation:
Given:
- The speed of Ben v_b = 3 mi/h
- The speed of Amanda v_a = 6 mi/h
- The total time taken to cover distance(d) by ben = t_b
Find:
How long will it be before Amanda catches up to Ben?
Solution:
- The distance d traveled by Ben:
d = v_b*t_b
d = 3*t_b
- The distance d traveled by Amanda:
d = v_a*t_a
d = 6*t_a
- Equate the distance as when they meet:
3*t_b = 6*t_a
- Where ,
t_b = t_a + 1.5
t_a = t_b - 1.5
- Substitute the time relationship in distance relationship:
3*t_b = 6*(t_b - 1.5)
3*t_b = 6*1.5
t_b = 2*1.5 = 3 h
- Hence, It would take 3 hours since Ben starts walking that amanda catches up.
Answer:
a). same as
b). less than
Explanation:
a). When a bicycle is moving, the linear speed at the top of the rear wheel is same as the linear speed at the top of the front wheel. Since the clown's bicycle is a rigid body, both the wheels that is the front wheel and the rear wheel will move with the same linear speed.
b). Since we know that angular speed varies inversely to the radius of the wheel.
That is ω = 1 / r
Since the rear wheel has twice the radius of that of the front wheel, therefore real wheel will have less angular speed than the front wheel.
Therefore, the angular speed of the rear wheel is less than the angular speed of the front wheel.
When boat is sunk into the liquid the net buoyancy on the boat is counterbalanced by weight of the boat
So here weight of the boat = Buoyancy force
let say boat is sunk by distance "h"
now we can say


now by above force balance equation we can write




so boat will sunk by total 5 mm distance
The value for the slope is <span>M=1.13</span>
To solve this problem it is necessary to apply the concepts related to the magnetic dipole moment in terms of the current and the surface area, as well as the current density, as a function of the current over the area.
Part A) By definition we know that magnetic dipole moment is

Where,
I = Current
S = Area

Replacing with our values we have that,

Re-arrange to find I,

Part B) To find the Current density we need to find the cross sectional area of the Wire:

Finally the current density is simply J

PART C) Finally to make the comparison with the given values we have to cross-sectional area would be

Therefore the current density would be

Comparing the two values we can see that the 2mm wire has a higher current density.