Answer:43.33 cm mark
Explanation:
Given
mass 1 is located at the 10 cm mark with weight of 15 kg
mass 2 is located at 60 cm mark with weight of 30 kg
string should be attached between them to balance the system
so the distance between the the two masses is 50 cm
For system to be balance torque of both the weight must nullify each other
Let us suppose string is at a distance of x cm from 15 kg mass so 30 kg mass is at a distance of 50-x cm
Balancing torque
so string should be at a mark of 10+33.33=43.33 cm
Answer:
57 eV
Explanation:
= separation between the plates = 4.9 mm = 0.0049 m
= Potential difference between the plates = 57 Volts
= magnitude of charge on proton = 1 e
= Kinetic energy of the proton
Using conservation of energy
Kinetic energy lost = Electric potential energy gained
Answer:
6.05 cm
Explanation:
The given equation is
2 aₓ(x-x₀)=( Vₓ²-V₀ₓ²)
The initial head velocity V₀ₓ =11 m/s
The final head velocity Vₓ is 0
The accelerationis given by =1000 m/s²
the stopping distance = x-x₀=?
So we can wind the stopping distance by following formula
2 (-1000)(x-x₀)=[]
x-x₀=6.05* m
=6.05 cm
Explanation:
The given data is as follows.
Mass of oxygen present = 100 mg = g
So, moles of oxygen present are calculated as follows.
n =
= moles
Diameter of cylinder = 6 cm = m
= 0.06 m
Now, we will calculate the cross sectional area (A) as follows.
A =
=
Length of tube = 11 cm = 0.11 m
Hence, volume (V) =
=
Now, we assume that the inside pressure is P .
And, = 100 kPa = 100000 Pa,
Pressure difference = 100000 - P
Hence, force required to open is as follows.
Force = Pressure difference × A
=
We are given that force is 173 N.
Thus,
= 173
Solving we get,
P =
= 38.65 kPa
According to the ideal gas equation, PV = nRT
So, we will put the values into the above formula as follows.
PV = nRT
T = 462.66 K
Thus, we can conclude that temperature of the gas is 462.66 K.
Answer:
This is a conceptual problem so I will try my best to explain the impossible scenario. First of all the two dust particles ara virtually exempt from any external forces and at rest with respect to each other. This could theoretically happen even if it's difficult for that to happen. The problem is that each of the particles have an electric charge which are equal in magnitude and sign. Thus each particle should feel the presence of the other via a force. The forces felt by the particles are equal and opposite facing away from each other so both charges have a net acceleration according to Newton's second law because of the presence of a force in each particle:
Having seen Newton's second law it should be clear that the particles are actually moving away from each other and will not remain at rest with respect to each other. This is in contradiction with the last statement in the problem.