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Oksana_A [137]
2 years ago
12

Light from a sodium lamp passes through a diffraction grating having 1000 slits per millimeter. The interference pattern is view

ed on a screen of 1.00m behind the grating. Two bright yellow fringes are visible 72.88cm and 73.00cm from the central maximum.
What are the wavelengths of these two fringes?
Physics
1 answer:
sashaice [31]2 years ago
3 0

Answer:

The wavelengths of these two fringes is  589.61 x 10∧9

Explanation:

d = slit width = 0.001/1000 = 1 x 10-6 m

X1 = Position of first fringe = 0.7288 m

X2 = Position of second fringe = 0.73 m

D = distance of the screen

tan\theta1 = X1/D   \Rightarrow\theta1 = tan-1(X1/D ) = tan-1(0.7288/1 ) = 36.085

tan\theta2 = X2/D   \Rightarrow\theta2 = tan-1(X2/D ) = tan-1(0.73/1 ) = 36.129

position of first bright fringe is given as

d Sin\theta1 = n\lambda1

for bright fringe , n = 1

d Sin\theta1 = \lambda1

\lambda1 = (1 x 10-6 ) Sin36.085 = 589 x 10-9

position of second bright fringe is given as

d Sin\theta2 = n\lambda2

for bright fringe , n = 1

d Sin\theta2 = \lambda2

\lambda2 = (1 x 10-6 ) Sin36.129 = 589.61 x 10-9

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The reaction energy of a reaction is the amount of energy released by the reaction. It is found by determining the difference in
solmaris [256]

Answer: the correct answer is 7.8026035971 x 10^(-13) joule

Explanation:

Use Energy Conservation. By ``alpha decay converts'', we mean that the parent particle turns into an alpha particle and daughter particles. Adding the mass of the alpha and daughter radon, we get

m = 4.00260 u + 222.01757 u = 226.02017 u .

The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is

Delta m = 226.02540 u - 226.02017 u = 0.00523 u ,

which is equivalent to an energy change of

Delta E = (0.00523 u)*(931.5MeV/1u)

Delta E = 4.87 MeV

Converting  4.87 MeV to Joules

1 joule [J] = 6241506363094 mega-electrón voltio [MeV]

4 mega-electrón voltio = 6.40870932 x 10^(-13) joule

4.87 mega-electrón voltio = 7.8026035971 x 10^(-13) joule

5 0
2 years ago
In a series circuit, a generator (1300 Hz, 12.0 V) is connected to a 14.0- resistor, a 4.40-μF capacitor, and a 6.00-mH inductor
klemol [59]

Answer:

(a) 2.8 V

(b) 5.6 V

(c) 9.8 V

Explanation:

Given:

Frequency of the generator (f) = 1300 Hz)

Terminal voltage (V) =12.0 V

Resistance of resistor (R) = 14.0 Ω

Capacitance of capacitor (C) = 4.40 μF = 4.40 × 10⁻⁶ F

Inductance of the inductor (L) = 6.00 mH = 6.00 × 10⁻³ H

In order to find the voltages across each, we first need to find the reactance and impedance.

Reactance of the inductor is given as:

X_L=2\pi f L\\\\X_L=2\times 3.14\times 1300\times 6.00\times 10^{-3}\\\\X_L=49\ \Omega

Reactance of the capacitor is given as:

X_C=\frac{1}{2\pi fC}\\\\X_C=\frac{1}{2\times 3.14\times 1300\times 4.40\times 10^{-6}}\\\\X_C =28\ \Omega

Now, impedance is given as:

Z=\sqrt{X_L^2+X_C^2}\\\\Z=\sqrt{(49)^2+(28)^2}\\\\Z=\sqrt{3185}=56.4\ \Omega

Current across the circuit is given as:

I=\frac{V}{Z}\\\\I=\frac{12}{56.4}=0.2\ A

As resistor, capacitor and inductor are connected in series, the current across each of them is same and equal to total current in the circuit.

(a)

Voltage across the resistor is given as:

V_R=IR\\\\V_R=0.2\times 14=2.8\ V

Therefore, the voltage across resistor is 2.8 V.

(b)

Voltage across the capacitor is given as:

V_C=IX_C\\\\V_C=0.2\times 28=5.6\ V

Therefore, the voltage across the capacitor is 5.6 V.

(c)

Voltage across the inductor is given as:

V_L=IX_L\\\\V_L=0.2\times 49=9.8\ V

Therefore, the voltage across the inductor is 9.8 V.

6 0
2 years ago
How much energy does a 50 kg rock have if it is sitting on the edge of a 15 m cliff?
noname [10]

Answer:

7350 J

Explanation:

The gravitational potential energy of the rock sitting on the edge of the cliff is given by:

U=mgh

where

m is the mass of the rock

g is the gravitational acceleration

h is the height of the cliff

In this problem, we have

m = 50 kg

g = 9.8 m/s^2

h = 15 m

Substituting numbers into the formula, we find:

U=(50 kg)(9.8 m/s^2)(15 m)=7350 J

3 0
2 years ago
An airplane flying at 115 m/s due east makes a gradual turn following a circular path to fly south. The turn takes 15 seconds to
ankoles [38]

Answer:

The magnitude of the centripetal acceleration during the turn is a=12.04\ m/s^2.

Explanation:

Given :

Speed to the airplane in circular path , v = 115 m/s.

Time taken by plane to turn , t= 15 s.

Also , the plane turns from east to south i.e. quarter of a circle .

Therefore, time taken to complete whole circle is , T=t\times 4=60\ s.

Now , Velocity ,

v=\dfrac{2\pi r}{T}\\\\115=\dfrac{2\times 3.14\times r}{60}\\\\r=1098.73\ m.

Also , we know :

Centripetal acceleration ,

a=\dfrac{v^2}{r}

Putting all values we get :

a=12.04\ m/s^2.

Hence , this is the required solution .

5 0
2 years ago
Water is projected from two rubber pipes at the same speed from one at an angle of 30°and from the other at 60°.why are the rang
cupoosta [38]
Thats hard...im not sure
4 0
2 years ago
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