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vfiekz [6]
2 years ago
15

Two basketball teams are resting during halftime. While they are resting, a truck driver asks them for help pushing his broken d

own truck to the top of a nearby hill so he can coast to the mechanic's shop. One team agrees to help, but the other refuses to help. The team that goes to push the truck is unable to get the truck to the top of the hill by themselves.
Physics
1 answer:
viva [34]2 years ago
7 0

Answer:

It is a superordinate goal because both teams could have helped with the task.

Explanation:

If both teams pushed then they could have made it happened

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a horse gallops a distance of 60 meters in 15 seconds. then, he stops to eat some grass for 20 seconds. next, he trots for 25 se
Neporo4naja [7]

Answer: check the attached graph for the answer

Explanation: Please find the attached file for the solution

3 0
1 year ago
Suppose a particle is accelerated through space by a constant 10-N force. Suddenly the particle encounters a second force of 10-
Harlamova29_29 [7]

Answer:

The particle will continue moving at constant velocity

Explanation:

When the particle encounters the second force of 10 N, the net force acting on the particle becomes zero, because the two forces are equal in magnitude but opposite in direction:

F_{net}=10 N-10 N=0

For Newton's second Law, the acceleration of the particle is proportional to the net force acting on it:

F_{net}=ma

Therefore, since F_{net}=0, the acceleration is zero (a=0) and so the particle will keep a constant velocity.

3 0
2 years ago
In advertising, which aspect does music help to address when a brand uses different types of music for advertising in the United
Oksi-84 [34.3K]

im pretty sure its entertainment

5 0
2 years ago
A student is studying the potential energy change of a 50 kg object raised 110 km above Earth's surface. What will be the percen
Law Incorporation [45]

Answer:

The percentage error is given by 99.9 %

Explanation:

Given:

Mass of object m = 50 kg

Height h = 110 km

From the formula of potential energy,

   U = mgh

Where g = 9.8 \frac{m}{s}

   U = 50\times 9.8 \times 110000

Here true value of potential energy,

   U = 50 \times 9.8 \times 11 \times 10^{4}

Approximate value of student,

   U = 50 \times 9.8 \times 110

Absolute error is given by

    = true value - approximate value

    = 50 \times 9.8 \times 11 \times 10^{4} - 50 \times 9.8 \times 110

    = 53846100

Hence percentage error,

    = \frac{53846100}{50 \times 9.8 \times 11 \times 10^{4} }

    = 0.999 \times 100 %

    = 99.9 %

Therefore, the percentage error is given by 99.9 %

7 0
2 years ago
A particle leaves the origin with an initial velocity v⃗ =(2.40 m/s)xˆv→=(2.40 m/s)x^ , and moves with constant acceleration a⃗
shtirl [24]

Answer:

distance stop 1.52m,

velocity  4.0 m/s y^

Explanation:

The movement of the particle is two-dimensional since it has acceleration in the x and y axes, the way to solve it is by working each axis independently.

a) At the point where the particle begins to return its velocity must be zero (Vfx = 0)

     Vfₓ = V₀ₓ + aₓ t  

     t = -  V₀ₓ/aₓ

     t = - 2.4/(-1.9)

     t=  1.26 s

At this time the particle stops, let's find his position

     X1 = V₀ₓ t + ½ aₓ t²

     X1= 2.4 1.26 + ½ (-1.9) 1.26²

     X1= 1.52 m

At this point the particle begins its return

b) The velocity has component x and y

   As a section, the X axis x Vₓ = 0 m/s is stopped, but has a speed on the y axis

    Vfy= Voy + ay t

    Vfy= 0 + 3.2 1.26

    Vfy = 4.0 m/s

the velocity is  

    V = (0 x^ + 4.0 y^) m/s

c) In order to make the graph we create a table of the position x and y for each time, let's start by writing the equations

      X = V₀ₓ t+ ½  aₓ t²

      Y = Voy t + ½  ay t²

      X= 2.4 t + ½ (-1.9) t²

      Y= 0 + ½ 3.2 t²

      X= 2.4 t – 0.95 t²

      Y=   1.6 t²

With these equations we build the table to graph, for clarity we are going to make two distance graph with time, one for the x axis and another for the y axis

                       Chart to graph

              Time (s)     x(m)            y(m)

                 0                0               0

                 0.5             0.960       0.4

          1       1.45          1.6

                 1.50      1.46      3.6

                2.00      1.00      6.4

7 0
2 years ago
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