Answer:
.c. −160°C
Explanation:
In the whole process one kg of water at 0°C loses heat to form one kg of ice and heat lost by them is taken up by ice at −160°C . Now see whether heat lost is equal to heat gained or not.
heat lost by 1 kg of water at 0°C
= mass x latent heat
= 1 x 80000 cals
= 80000 cals
heat gained by ice at −160°C to form ice at 0°C
= mass x specific heat of ice x rise in temperature
= 1 x .5 x 1000 x 160
= 80000 cals
so , heat lost = heat gained.
The output of the machine is
(output work) = (output force) x (distance)
450 N-m = (output force) x (3 meters)
Divide each side
by 3 meters: Output force = (450 N-m) / (3 m)
= 150 newtons .
With all the information given about the output work, we don't need
to know anything about the input work, or even the fact that we're
dealing with a machine.
It's comforting, though, to look back and notice that the output work
(450 N-m) is not more than the input work (500 N-m). So everything
is nice and hunky-dory.
___________________________________
Well, my goodness !
I didn't even need to go through all of that.
Given:
-- The input force to the machine is 50 newtons.
-- The mechanical advantage of the machine is 3 .
That right there tells us that
-- The output force of the machine is 150 newtons.
We don't need any of the other given information.
Answer:
1.17894 m
Explanation:
The rock is at one end of the rod which is 0.211 m from the fulcrum
F = Force
d = Distance
L = Length of rod
M = Mass of rock = 325 kg
g = Acceleration due to gravity = 9.81 m/s²
Torque
Torque of man
Torque of rock
The torques acting on the system is conserved
The length of the rod is 1.17894 m
Answer:
2.25 kg
Explanation:
Length, L = 6 m
tension, T = 600 N
velocity, v = 40 m/s
The formula for the velocity is given by
where, μ is mass per unit length
μ = 0.375
m / L = 0.375
m = 0.375 x 6 = 2.25 kg
Thus, the mass of rope is 2.25 Kg.
