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olasank [31]
2 years ago
13

Calculate the volume occupied by 25.2 g of co2 at 0.84 atm and 25°c. r = 0.08206 latm/kmol.

Physics
1 answer:
Nitella [24]2 years ago
5 0

Answer:

16.68 L

Explanation:

First of all, we need to calculate the number of moles corresponding to 25.2 g of CO2.

The molar mass of CO2 is 44.01 g/mol, therefore the number of moles is:

n=\frac{m}{M_m}=\frac{25.2 g}{44.01 g/mol}=0.573 mol

So now we can use the ideal gas equation:

pV=nRT

where:

p = 0.84 atm is the gas pressure

V = ? is the volume

n = 0.573 mol is the number of moles

R = 0.08206 L atm / K mol is the gas constant

T = 25°c = 298 K is the gas temperature

Substituting into the equation and re-arranging it, we find the volume:

V=\frac{nRT}{p}=\frac{(0.573 mol)(0.08206 Latm/Kmol)(298 K)}{0.84 atm}=16.68 L

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MaRussiya [10]

Answer:

a_c=9.66\frac{m}{s^2}

Explanation:

The centripetal acceleration is given by:

a_c=\frac{v^2}{r}(1)

Here v is the linear speed and r is the radius of the circular motion. v is defined as the distance traveled to make one revolution (2\pi r) divided into the time takes to make one revolution, that is, the period (T).

v=\frac{2\pi r}{T}(2)

Replacing (2) in (1) and replacing the given values:

a_c=\frac{(\frac{2\pi r}{T})^2}{r}\\a_c=\frac{4\pi^2 r}{T^2}\\a_c=\frac{4\pi^2 (1.85m)}{(2.75s)^2}\\a_c=9.66\frac{m}{s^2}

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1 year ago
A teacher uses the model that little invisible gremlins speed up or slow down objects and the direction they push gives the dire
Vlada [557]
Newtons second law.. <span>The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.</span>
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1 year ago
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A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, take
adell [148]

Answer:

F_{x}=2.31N to the right.

F_{y}=2.1N to in the upwards direction.

Explanation:

In order to solve this problem, we must first start by drawing a diagram of the situation. (See attached diagram).

So, remember that a force is determined by multiplying the mass of the parcticle by its acceleration:

F=ma

so in order to find the components of the force, we need to start by finding its acceleration.

Acceleration is found by using the following formula:

a=\frac{V_{f}-V{0}}{t}

so we can subtract the two vectors, like this:

a=\frac{(6.00i+4.0j)m/s-1.60i m/s}{8s}

which yields:

a=\frac{(4.4i+4.0j)m/s}{8s}

or:

a=(0.55i + 0.5j) m/s^{2}

so now I can find the components of the force:

F=(4.2kg)(0.55i + 0.5j) m/s^{2}

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F=(2.31i+2.1j)N

so the components of the force are:

F_{x}=2.31N to the right.

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6 0
1 year ago
If you have to apply 40n of force on a crowbar to lift a rock that weights 400n, what is the actual mechanical advantage of the
Mrrafil [7]
The mechanical advantage is defined as the ratio between the force produced by a machine and the force applied in input:
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3 0
1 year ago
A physics student with too much free time drops a watermelon from a roof of a building, hears the sound of the watermelon going
tatiyna

Answer:

28.6260196842 m

Explanation:

Let h be the height of the building

t = Time taken by the watermelon to fall to the ground

Time taken to hear the sound is 2.5 seconds

Time taken by the sound to travel the height of the cliff = 2.5-t

Speed of sound in air = 340 m/s

For the watermelon falling

s=ut+\frac{1}{2}at^2\\\Rightarrow h=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow h=\frac{1}{2}\times 9.81\times t^2

For the sound

Distance = Speed × Time

\text{Distance}=340\times (2.5-t)

Here, distance traveled by the stone and sound is equal

\frac{1}{2}\times 9.81\times t^2=340\times (2.5-t)\\\Rightarrow 4.905t^2=340\times (2.5-t)\\\Rightarrow t^2=\frac{340}{4.905}(2.5-t)\\\Rightarrow t^2+69.3170234455t-173.292558614=0

t=\frac{-69.31702\dots +\sqrt{69.31702\dots ^2-4\cdot \:1\cdot \left(-173.29255\dots \right)}}{2\cdot \:1},\:t=\frac{-69.31702\dots -\sqrt{69.31702\dots ^2-4\cdot \:1\cdot \left(-173.29255\dots \right)}}{2\cdot \:1}\\\Rightarrow t=2.4158\ s\ or\ -71\ seconds

The time taken to fall down is 2.4158 seconds

h=\frac{1}{2}\times 9.81\times 2.4158^2=28.6260196842\ m

Height of the buidling is 28.6260196842 m

7 0
2 years ago
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