Answer:
Mass of the pull is 77 kg
Explanation:
Here we have for
Since the rope moves along with pulley, we have
For the first block we have
T₁ - m₁g = -m₁a = -m₁g/4
T₁ = 3/4(m₁g) = 323.4 N
Similarly, as the acceleration of the second block is the same as the first block but in opposite direction, we have
T₂ - m₂g = m₂a = m₂g/4
T₂ = 5/4(m₂g) = 134.75 N
T₂r - T₁r = I·∝ = 0.5·M·r²(-α/r)
∴
Mass of the pull = 77 kg.
Answer:
Time period of the motion will remain the same while the amplitude of the motion will change
Explanation:
As we know that time period of oscillation of spring block system is given as
now we know that
M = mass of the object
k = spring constant
So here we know that the time period is independent of the gravity
while the maximum displacement of the spring from its mean position will depends on the gravity as
so we can say that
Time period of the motion will remain the same while the amplitude of the motion will change
Answer: It would increase.
Explanation:
The equation for determining the force of the gravitational pull between any two objects is:
Where G is the universal gravitational constant, m1 is the mass of one body, m2 is the mass of the other body, and r^2 is the distance between the two objects' centers squared.
Assuming the Earth's mass but not its diameter increased, in the equation above m1 (the term usually indicative of the object of larger mass) would increase, while the r^2 would not.
Thus, it goes without saying that, with some simple reasoning about fractions, an increasing numerator over a constant denominator would result in a larger number to multiply by G, thus also meaning a larger gravitational strength between Earth and whatever other object is of interest.