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Verdich [7]
2 years ago
14

Suppose Earth's mass increased but Earth's diame-

Physics
1 answer:
navik [9.2K]2 years ago
7 0

Answer: It would increase.

Explanation:

The equation for determining the force of the gravitational pull between any two objects is:

F = G \frac{m1m2}{r^2}

Where G is the universal gravitational constant, m1 is the mass of one body, m2 is the mass of the other body, and r^2 is the distance between the two objects' centers squared.

Assuming the Earth's mass but not its diameter increased, in the equation above m1 (the term usually indicative of the object of larger mass) would increase, while the r^2 would not.

Thus, it goes without saying that, with some simple reasoning about fractions, an increasing numerator over a constant denominator would result in a larger number to multiply by G, thus also meaning a larger gravitational strength between Earth and whatever other object is of interest.

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The potential energy of a 40 kg cannon ball is 14000 J. How high was the cannon ball to have this much potential energy?
Fynjy0 [20]
The formula for potential energy is PE=mgh
It can have that high of a potential energy if it's relative height what super high.
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2 years ago
Takumi works in his yard for 45 minutes each Saturday. He works in the morning, and he wears sunscreen and a hat each time he wo
MrRa [10]

Explanation :

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So, the correct option is (b) "the severity of stochastic effects, such as cancer".

7 0
3 years ago
Read 2 more answers
A 1150 kg car is on a 8.70° hill. using x-y axis tilted down the plane, what is the x-component of the weight?
Fed [463]
I assume the x-y axis are tilted such that the x-axis is parallel to the surface of the hill while the y-axis is perpendicular to it.

In this case, the x-component of the weight is given by:
W_x =mg \sin \theta
where
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g is the acceleration of gravity
\theta is the angle of the hill

Substituting numbers into the formula, we find
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6 0
2 years ago
A balloon is at a height of 81m and is ascending upwards with a velocity of 12m/s. A body of 2kg weight is dropped from it. If g
kap26 [50]
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7 0
2 years ago
The pail is rotated at a constant rate so it has the minimum speed at all points along its circular path. The water has mass m.
Alisiya [41]

Answer:

Explanation:

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mg = mv² / r ( r is radius of  vertical circular path )

v = √ rg

At the bottom position its velocity will be increased due to loss of potential energy

so 1/2 m V² = 1/2 m v² + mg x 2r  

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If R be the reaction force at the bottom by bottom of pail

R - mg = mV² / r

R = mg +mV² / r

= mg + m x 5gr / r

R = 6mg

This is the magnitude of the force exerted by the water on the bottom of the pail .

7 0
2 years ago
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