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2 years ago

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If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal fo

rce.

2 answers:

Allisa [31]2 years ago

8 0

Answer:

$108\ N$

Explanation:

Mass of object, $m=1.50\ kg.$

Length of string, $r=0.50\ m.$

Tangential speed, $v_t=6.0\ m/s.$

Now, centripetal force F of a object moving in given radius r and mass m moving with velocity v.

Here , object moves along the ends of string. Therefore, radius is equal to length of string.

$F=\dfrac{m \times v_t^2}{r}.$

Putting values of m,v and r in above equation.

We get, $F=\dfrac{1.50\times (6.0)^2}{0.50} \ N=108 \ N.$

Hence, this is the required solution.

rosijanka [135]2 years ago

5 0

You should get about 110 for an answer

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Answer

given,

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A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kgÂ·m2. If the arms are pulled in so t

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a) 6.25 rad/s

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$L=I\omega$

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