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Shtirlitz [24]
2 years ago
14

A car with a mass of 1400kg is being driven along the motorway at 30m/s. Calculate the kinetic energy of the car

Physics
1 answer:
Umnica [9.8K]2 years ago
3 0

Answer:

6.3 \cdot 10^5 J

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the car in this problem,

m = 1400 kg

v = 30 m/s

Therefore, the kinetic energy of the car is

K=\frac{1}{2}(1400)(30)^2=6.3 \cdot 10^5 J

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What is the threshold frequency for sodium metal if a photon with frequency 6.66 × 1014 s−1 ejects a photon with 7.74 × 10−20 J
FrozenT [24]

Answer:

5.5 × 10^14 Hz or s^-1

no orange light has less frequency so no photoelectric effect

Explanation:

hf = hf0 + K.E

HERE h is Planck 's constant having value 6.63 × 10 ^-34 J s

f is frequency of incident photon and f0 is threshold frequency

hf0 = hf- k.E

6.63 × 10 ^-34 × f0 = 6.63 × 10 ^-34× 6.66 × 10^14 - 7.74× 10^-20

6.63 × 10 ^-34 × f0 = 3.64158×10^-19

                           f0 = 3.64158×10^-19/ 6.63 × 10 ^-34

                           f0 = 5.4925 × 10^14

                            f0 =5.5 × 10^14 Hz or s^-1

frequency of orange light is 4.82 × 10^14 Hz which is less than threshold frequency hence photo electric effect will not be observed for orange light

8 0
2 years ago
Which of the following substances will show the smallest change in temperature when equal amounts of energy are absorbed?
SSSSS [86.1K]
It would be water because if you freeze it than you will still be able to see it and if you boil it than you will be able to see it disappear.
3 0
2 years ago
Read 2 more answers
the steel bed of a suspension bridge is 200m long at 20 C. If the extremes of temperature to which it might be exposed are -30 C
raketka [301]

Answer:

The steel bed will contract by  0.13 m, and expand by 0.052 m

Explanation:

For contraction,

α = ΔL/(LΔθ)..................... Equation 1

Where α = Linear expansivity of  steel, ΔL = decrease in length/ Increase in length, L = Original length, Δθ = Change in temperature

make ΔL the subject of the equation

ΔL = α(LΔθ)................. Equation 2

Given: α = 13×10⁻⁶/C, L = 200 m, Δθ = -30-20 = -50 °C

Substitute into equation 2

ΔL = 13×10⁻⁶(200)(-50)

ΔL = -0.13 m

Similarly, For expansion,

Using equation 2

ΔL =  α(LΔθ)

Given: α = 13×10⁻⁶/C, L = 200 m, Δθ = 40-20 = 20  °C

Substitute into equation 2

ΔL =  13×10⁻⁶(200)(20)

ΔL = 0.052 m.

Hence the steel bed will contract by  0.13 m, and expand by 0.052 m

3 0
2 years ago
What is the Physics Primer?
Elza [17]

Answer:

A. a set of mathematically topics that are relevant to introductory physics.

Explanation:

The physics primer is not defined as the online comprehensive mathematics textbooks. It is the set of topics of mathematics which gives students trouble and remember.

Therefore, it is defined as the process of physics problem solving. So, mathematically skills are covered in physics course as a primer related success.

Therefore, it is a set of topics of mathematics that are relevent to introductory physics.

7 0
2 years ago
Read 2 more answers
A Porsche 944 Turbo has a rated engine power of 217hp . 30% of the power is lost in the drive train, and 70% reaches the wheels.
scZoUnD [109]

Explanation:

(a)  It is given that two-third of weight is over the drive wheels. So, mathematically, w = \frac{2}{3}mg.

Hence, maximum force is expressed as follows.

                F_{max} = \mu_{s} \times w

           m \times a_{max} = \mu_{s} (\frac{2}{3} mg)

Hence, the maximum acceleration is calculated as follows.

             a_{max} = \frac{2}{3} \mu_{s} \times g

                          = \frac{2}{3} \times 1.00 \times 9.8 m/s^{2}

                          = 6.53 m/s^{2}

Hence, the maximum acceleration of the Porsche on a concrete surface where μs = 1 is 6.53 m/s^{2}.

(b)  Since, 30% of the power is lost in the drive train. So, the new power is 70% of P_{max}.

That is,   new power = 0.7 \times P_{max}

Now, the expression for power in terms of force and velocity is as follows.

                      P = F_{max} \nu

              0.7 P_{max} = ma_{max} \nu

Therefore, speed of the Porsche at maximum power output is as follows.

            \nu = 0.7 \times \frac{P_{max}}{ma_{max}}

                      = 0.7 \times \frac{217 hp \times \frac{746 W}{1 hp}}{1500 kg \times 6.53 m/s^{2}}

                      = 11.568 m/s

                      = 11.57 m/s

Therefore, speed of the Porsche at maximum power output is 11.57 m/s.

(c)   The time taken will be calculated as follows.

             time = \frac{\text{velocity}}{\text{acceleration}}

                     = \frac{11.57 m/s}{6.53 m/s^{2}}

                     = 1.77 s

Therefore, the Porsche takes 1.77 sec until it reaches the maximum power output.

6 0
2 years ago
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