Answer:
Yes, the capacitor's Q load varies inversely proportional to the distance between plates.
Explanation:
In the attached files you see the inverse relationship between capacity and distance between plates "d".
In the following formula we see its relationship with the "Q" load
To help you I need to assume a wavelength and then calculate the momentum.
The momentum equation for photons is:
p = h / λ , this is the division of Plank's constant by the wavelength.
Assuming λ = 656 nm = 656 * 10 ^ - 9 m, which is the wavelength calcuated in a previous problem, you get:
p = (6.63 * 10 ^-34 ) / (656 * 10 ^ -9) kg * m/s
p = 1.01067 * 10^ - 27 kg*m/s which must be rounded to three significant figures.
With that, p = 1.01 * 10 ^ -27 kg*m/s
The answers are rounded to only 2 significan figures, so our number rounded to 2 significan figures is 1.0 * 10 ^ - 27 kg*m/s
So, assuming the wavelength λ = 656 nm, the answer is the first option: 1.0*10^-27 kg*m/s.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The angle between shuttle's velocity and the Earth's field is 
Explanation:
From the question we are told that
The length of eire let out is 
The emf generated is 
The earth magnetic field is 
The speed of the shuttle and tether is 
The emf generated is mathematically represented as

making
the subject of the formula
![\theta = sin ^{-1}[ \frac{\epsilon}{L * B *v} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20%20sin%20%5E%7B-1%7D%5B%20%5Cfrac%7B%5Cepsilon%7D%7BL%20%20%2A%20B%20%20%2Av%7D%20%5D)
substituting values
![\theta = sin ^{-1}[ \frac{40}{250 * (5*10^{-5}) *(7.80 *10^{3})} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20%20sin%20%5E%7B-1%7D%5B%20%5Cfrac%7B40%7D%7B250%20%20%2A%20%285%2A10%5E%7B-5%7D%29%20%20%2A%287.80%20%2A10%5E%7B3%7D%29%7D%20%5D)
