Two students grab a slinky and start waving it up and down. A third student counts the number of waves that pass by every second
and measures the distance between the wave peaks. This data is recorded and a graph is made to show the results.
In looking at the graph, what wave property is remaining constant over the experiment?
In looking at the graph, what wave property is remaining constant over the experiment?
2 answers:
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Explanation:
Given that,
Angular velocity = 0.240 rev/s
Angular acceleration = 0.917 rev/s²
Diameter = 0.720 m
(a). We need to calculate the angular velocity after time 0.203 s
Using equation of angular motion
Put the value in the equation
The angular velocity is 0.426 rev/s.
(b). We need to calculate the tangential speed of the blade
Using formula of tangential speed
Put the value into the formula
The tangential speed of the blade is 0.963 m/s.
(c). We need to calculate the magnitude at of the tangential acceleration
Using formula of tangential acceleration
Put the value into the formula
The tangential acceleration is 2.074 m/s².
Hence, This is required solution.
Answer:
Explanation:
Given:
The accelerated energy, U = 1.25 MeV = 1.25 × 10⁶ eV
we know,
1 eV = 1.6 × 10⁻¹⁹ J
thus,
1.25 eV = (1.6 × 10⁻¹⁹) × (1.25) J = 2 × 10⁻¹³ J
Now, Applying the law of conservation of energy, the energy due to acceleration will be equal to the kinetic energy
mathematically,
K.E = U
where,
m = mass of the particle = 1.67 × 10⁻²⁷ kg
v = velocity of the particle
on substituting the values we get
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