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charle [14.2K]
2 years ago
6

a 1250 kg car accelerates from rest to 6.13m/s over a distance of 8.58m calculate the average force of traction

Physics
1 answer:
iogann1982 [59]2 years ago
3 0
Use formula, v^2= u^2 + 2as.
The "v" and the "s" of the formula are given.
Since u is 0, just use f=ma.
I hope this helped!
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An object on a number line moved from x = 15 cm to x = 165 cm and then
olasank [31]

Answer:

v_avg = 2.9 cm/s

Explanation:

The average velocity of the object is the sum of the distance of all its trajectories divided the time:

v_{avg}=\frac{x_{all}}{t}

x_all is the total distance traveled by the object. In this case you have that the object traveled in the first trajectory 165cm-15cm = 150cm, and in the second one, 165cm - 25cm = 140cm

Then, x_all = 150cm + 140cm = 290cm

The average velocity is, for t = 100s

v_{avg}=\frac{290cm}{100s}=2.9\frac{cm}{s}

hence, the average velocity of the object in the total trajectory traveled is 2.9 cm/s

3 0
1 year ago
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12*8A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring 13 feet. The ball is started in
max2010maxim [7]

Answer:

See attached pictures.

Explanation:

See attachments for explanation.

6 0
1 year ago
A car drives 16 miles south and then 12 miles west. What is the magnitude of the car’s displacement? 4 miles 16 miles 20 miles 2
Ostrovityanka [42]
For this case, what we can do is use the Pythagorean theorem to find the magnitude of the displacement of the car.
 We have then
 d ^ 2 = 16 ^ 2 + 12 ^ 2

 From here, we clear the value of d.
 We have then:
 d =  \sqrt{16 ^ 2 + 12 ^ 2} 

 Rewriting:
 d = \sqrt{256 + 144}
 d = \sqrt{400}
 d = 20 miles

 Answer:
 
The magnitude of the car's displacement is:
 
d = 20 miles
7 0
1 year ago
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An ambulance moving at 42 m/s sounds its siren whose frequency is 450 hz. a car is moving in the same direction as the ambulance
Korvikt [17]
(a) Since the ambulance and the car are moving one relative to each other, we have to use the general formula of the Doppler effect, which gives us the shift of the frequency of the siren as heard by an observer in the car:
f'=( \frac{v+v_o}{v+v_s} )f
where
f' is the apparent frequency as heard by the observer in the car
v is the velocity of the wave 
v_o is the velocity of the observer (positive if it is moving towards the source, negative if it is moving away)
v_s is the velocity of the source (positive if the source is moving away from the observer, negative if is is moving towards it)
f is the real frequency of the sound

In the first part of the problem:
v=343 m/s (speed of the sound wave)
v_o =-25 m/s (the car is moving away from the ambulance)
v_s = -42 m/s (the ambulance is moving towards the car)
f=450 Hz (original frequency of the sound)

If we plug the numbers into the formula, we find
f'=( \frac{343 m/s-25 m/s}{343 m/s-42 m/s} )(450 Hz)=475 Hz

b) This time, the ambulance passes the car, so the ambulance is now moving away from the car; this means that v_s must be positive:
v_s=+42 m/s
Moreover, the car is now moving towards the ambulance, so we should reverse also the sign of v_o:
v_o=+25 m/s
All the other data do not change, so if we use the same formula as before, we find
f'=( \frac{343 m/s+25 m/s}{343 m/s+42 m/s} )(450 Hz)=430 Hz
8 0
1 year ago
To start the analysis of this circuit you must write energy conservation (loop) equations. Each equation must involve a round-tr
REY [17]

Answer:

Explanation:

Electric field talks about a region around a charged particle or object within which a force would be exerted on other charged particles or objects. to find the electric field inside the bulb we will apply the electric filed formula.

Please kindly check attachment for step by step explaination.

6 0
2 years ago
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