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sveticcg [70]
2 years ago
8

Ellen does an experiment by releasing a ball from a height of 1 m above each floor in a tall building. She records the time it t

akes the ball to reach the floor.
Which question is Ellen most likely investigating?

How does distance affect the gravitational force on objects?
How does distance affect the electromagnetic force on objects?
Does height affect the strong force acting on a moving ball?
Does height affect the weak force acting on a moving ball?
Physics
2 answers:
Anuta_ua [19.1K]2 years ago
7 0

Answer:

The question that Ellen most likely investigating is "How does distance affect the gravitational force on objects?"

Explanation:

harina [27]2 years ago
4 0
Answer is A because I got the question right
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Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and
lorasvet [3.4K]

Answer: One canister contains 1.03 Kg of fuel,

Explanation:

The density is defined as the relation between the mass and the volume p=\frac{m}{v}

First of all you need to have the same units for volume and density, so:

For the volume,

1.45 L * \frac{1.10*10^{-3}m^{3}  }{1 L} = 1.45 *10^{-3} m^{3}

For the density,

p = 0.710\frac{g}{cm^{3} } *\frac{1cm^{3} }{1*10^{-6}m^{3}  }*\frac{1 Kg}{1*10^{3}g } = 710\frac{Kg}{m^{3} }

From the density equation we have m=p*v, so:

710\frac{Kg}{m^{3} } *1.45*10^{-3} m^{3} = 1.03Kg

4 0
2 years ago
A rescue helicopter wants to drop a package of supplies to isolated mountain climbers on a rocky ridge 200 m below. If the helic
andreev551 [17]

Answer:

a) 447.21m

b) -62.99 m/s

c)94.17 m/s

Explanation:

This situation we can divide in 2 parts:

⇒ Vertical : y =-200 m

y =1/2 at²

-200 = 1/2 *(-9.81)*t²

t= 6.388766 s

⇒Horizontal: Vx = Δx/Δt

Δx = 70 * 6.388766 = 447.21 m

b) ⇒ Horizontal

Vx = Δx/Δt ⇒ 70 = 400 /Δt

Δt= 5.7142857 s

⇒ Vertical:

y = v0t + 1/2 at²

-200 = v(5.7142857) + 1/2 *(-9.81) * 5.7142857²

v0= -7 m/s  ⇒ it's negative because it goes down.

v= v0 +at

v= -7 + (-9.81) * 5.7142857

v= -62.99 m/s

c) √(70² + 62.99²) = 94.17 m/s

8 0
2 years ago
By standard convention, both the electric potential and the the electric potential energy between two charges is taken to be zer
shusha [124]

Answer: at when distance r = infinity.

Explanation: The formulae for the electric potential of an electric charge to an arbitrary point is given by the formulae below

V = q/4πεr

V = electric potential (volts)

q = magnitude of electric charge

ε = permittivity of free space

r = distance between arbitrary point and charge.

In the equation above, it can be seen that only electric potential (v) and distance (r) is a variable, and there is an inverse relationship between them (an increase in one leads to a decrease in the other)

Thus to have zero value of electric potential (v= 0) we have to have the largest value of r ( r = infinity).

Same goes for electric potential energy between two charges, the formulae is given below as

W = q1 *q2/4πεr

W= electric potential energy

q1 = magnitude of first charge.

q2 = magnitude of second charge

ε = permittivity of free space

r = distance between arbitrary point and charge.

Also, all values are constant aside from electric potential energy (w) and distance (r) which have an inverse relationship.

Thus to have zero value of electric potential energy (w =0), we have to get an infinite value of distance ( r =infinity)

6 0
2 years ago
Which statements describe a situation with a displacement of zero? Check all that apply. traveling south for 30 miles, then turn
velikii [3]
<span>The term "displacement" includes a change of position or change in an innate characteristic. The first option would have someone travel in an L-shape, which definitely is a change in position from the starting point. The second option of Ferris wheel with the same entrance and exit does not involve overall displacement since a person would return to the same place they began. The third option of walking around the block does not involve overall displacement since, again, the person would return to the same place they began. The fourth option of an escalator ride does involve overall displacement because a person would finish their journey in a different vertical location from where they started. The last option does not involve overall displacement because one lap around a track will return you to the same place you began.</span>
5 0
2 years ago
Read 2 more answers
What is the work done by the 200.-N tension shown if it is used to drag the 150-N crate 25 m across the floor at a constant spee
WINSTONCH [101]

Answer:

0 J

Explanation:

Work equals force times distance, but the force is zero because the crate being dragged will have zero acceleration. Force equals mass times acceleration and since acceleration is zero, force has to equal zero as well. Since the force is zero, the work required also has to be zero.

8 0
1 year ago
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