Answer:
Given the potential, 
The components of the electric field are:


Let's calculate the potential difference for all given points.



Solving for A, we have:



Solving for B, we have:


Solving for C, we have:

For all given points, let's calculate the magnitude of electric field as follow:


Solving for l, we have:

From above, A = -6




Solving for m, we have:

From above, B = -4



Solving for n, we have:

From above, C = -2

We are given an electromagnetic wave with a frequency of 5.09 x 10^14 Hz and travelling through a transparent medium. If the medium was vacuum, the speed of the wave would be equal to the speed of light. Otherwise, the main factor that would determine the speed of the wave is its wavelength.
F= (speed)/(wavelength)
Therefore, speed = Frequency x wavelength
V = 68m/s
Answer: Mass of the planet, M= 8.53 x 10^8kg
Explanation:
Given Radius = 2.0 x 106m
Period T = 7h 11m
Using the third law of kepler's equation which states that the square of the orbital period of any planet is proportional to the cube of the semi-major axis of its orbit.
This is represented by the equation
T^2 = ( 4π^2/GM) R^3
Where T is the period in seconds
T = (7h x 60m + 11m)(60 sec)
= 25860 sec
G represents the gravitational constant
= 6.6 x 10^-11 N.m^2/kg^2 and M is the mass of the planet
Making M the subject of the formula,
M = (4π^2/G)*R^3/T^2
M = (4π^2/ 6.6 x10^-11)*(2×106m)^3(25860s)^2
Therefore Mass of the planet, M= 8.53 x 10^8kg