Answer:
(2) −1 e
Explanation:
A quark is the lightest elementary particles which form hadron such as proton and neutron. A quark has fractional charge.
Up, charm and top quarks have charge where as down, strange and bottom quarks have
charge.
The antiparticle of up quark is antiup quark and has charge charge.
The antiparticle of down quark is antidown quark and has charge charge.
An antibaryon is composed of two anti-up quark and one anti-down quark.
Net charge of the anti-baryon is:
Thus, antibaryon has -1e charge.
Answer:
Explanation:
Given
Original Frequency
apparent Frequency
There is change in frequency whenever source move relative to the observer.
From Doppler effect we can write as
where
apparent frequency
v=velocity of sound in the given media
velocity of source
velocity of observer
here
i.e.fork acquired a velocity of
distance traveled by fork is given by
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
Answer:
v = 2.21 m/s
Explanation:
The foreman had released the box from rest at a height of 0.25 m above the ground.
We need to find the speed of the crate when it reaches the bottom of the ramp. Let v is the velocity at the bottom of the ramp. It can be calculated using conservation of energy as follows :
So, its velocity at the bottom of the ramp is 2.21 m/s.
The stone reaches the wall at a height of <u>1.62 m</u>.
The stone lands at a point <u>24.5 m</u> from the point of projection.
The stone is projected horizontally with a velocity u at a height <em>h</em> from the ground. The wall is located at a distance <em>x</em> from the point of projection. The stone takes a time <em>t</em> to reach the wall and in the same time the stone falls a vertical distance <em>y</em>.
The horizontal distance <em>x</em> is traveled with a constant velocity <em>u</em>.
Calculate the time taken <em>t</em>.
The stone's initial vertical velocity is zero. It falls through a distance <em>y</em> in the time <em>t</em> under the action of acceleration due to gravity <em>g</em>.
The height <em>h₁ </em>of the stone above the ground when it reaches the wall is given by,
When the stone reaches the wall, its height from the ground is <u>1.62m.</u>
The stone thus crosses over the wall, since the height of the wall is 1 m. It reaches the ground at a distance <em>R</em> from the point of projection. If the time taken by the stone to reach the ground is <em>t₁, </em>then,
Calculate the time taken by the stone to reach the ground.
The horizontal distance traveled by the stone is given by,
The stone lands at point 24.5 m from the point of projection and 10.5 m from the wall.
Answer:
a)106.48 x 10⁵ kg.m²
b)144.97 x 10⁵ kgm² s⁻¹
Explanation:
a)Given
m = 5500 kg
l = 44 m
Moment of inertia of one blade
= 1/3 x m l²
where m is mass of the blade
l is length of each blade.
Putting all the required values, moment of inertia of one blade will be
= 1/3 x 5500 x 44²
= 35.49 x 10⁵ kg.m²
Moment of inertia of 3 blades
= 3 x 35.49 x 10⁵ kg.m²
= 106.48 x 10⁵ kg.m²
b) Angular momentum 'L' is given by
L = x ω
where,
= moment of inertia of turbine i.e 106.48 x 10⁵ kg.m²
ω=angular velocity =2π f
f is frequency of rotation of blade i.e 13 rpm
f = 13 rpm=>= 13 / 60 revolution per second
ω = 2π f => 2π x 13 / 60 rad / s
L= x ω =>106.48 x 10⁵ x 2π x 13 / 60
= 144.97 x 10⁵ kgm² s⁻¹