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2 years ago

Dao makes a table to identify the variables used in the equations for centripetal acceleration.

Physics

2 answers:

LiRa [457]2 years ago

6 0

Answer : The variables used in the equations for centripetal acceleration are, radius and tangential speed.

Explanation :

Centripetal acceleration : It is defined as any object moving in a circular path will have some acceleration vector that pointed towards the center of the circle.

Formula used for centripetal acceleration is,

$a_c=\frac{v^2}{r}$

where,

$a_c$ = centripetal acceleration

r = radius of path

v = velocity or speed of an object or tangential speed

In the equation of centripetal acceleration, the radius and tangential speed are the variables.

Andru [333]2 years ago

3 0

Answer:

X: tangential speed

Y: radius

Explanation:

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2 years ago

A rocket is fired in deep space, where gravity is negligible. If the rocket has a mass of 6000 kg and ejects gas at a relative v

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2 years ago

A 2.0 m × 4.0 m flat carpet acquires a uniformly distributed charge of −10 μC after you and your friends walk across it several

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Answer:

The charge on the dust particle is $q_d = 6.94 *10^{-13} \ C$

Explanation:

From the question we are told that

The length is $l = 2.0 \ m$

The width is $w = 4.0 \ m$

The charge is $q = -10\mu C= -10*10^{-6} \ C$

The mass suspended in mid-air is $m_a = 5.0 \mu g = 5.0 *10^{-6} \ g = 5.0 *10^{-9} \ kg$

Generally the electric field on the carpet is mathematically represented as

$E = \frac{q}{ 2 * A * \epsilon _o}$

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substituting values

$E = \frac{-10*10^{-6}}{ 2 * (2 * 4 ) * 8.85*10^{-12}}$

$E = -70621.5 \ N/C$

Generally the electric force keeping the dust particle on the air equal to the force of gravity acting on the particles

$F__{E}} = F__{G}}$

=> $q_d * E = m * g$

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2 years ago

If you were to separate all of the electrons and protons in 1.00 g (0.001 kg) of matter, you’d have about 96,000 C of positive c

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Answer:

The attractive force between them is $1.296 \times 10^{18}$ N

Explanation:

Given:

Charge $q = 96000$ C

Distance between two charges $r = 8$ m

According to the coulomb's law,

$F = \frac{kq^{2} }{r^{2} }$

Where $k = 9 \times 10^{9}$ = force constant.

$F = \frac{9 \times 10^{9} \times (96000)^{2} }{8^{2} }$

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2 years ago

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Answer:

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