Answer:
The tension in the rope is 281.60 N.
Explanation:
Given that,
Length = 3.0 m
Weight = 600 N
Distance = 1.0 m
Angle = 60°
Consider half of the ladder,
let tension be T, normal reaction force at ground be F, vertical reaction at top hinge be Y and horizontal reaction force be X.
....(I)
.....(II)
On taking moment about base

Put the value into the formula


....(III)
We need to calculate the force for ladder


We need to calculate the tension in the rope
From equation (3)




Hence, The tension in the rope is 281.60 N.
Answer:
I = 69.3 μA
Explanation:
Current through the straight wire, I = 3.45 A
Number of turns, N = 5 turns
Diameter of the coil, D = 1.25 cm
Resistance of the coil, 
Distance of the wire from the center of the coil, d = 20 cm = 0.2 m
The magnetic field, B₁, when the wire is at a distance, d, from the center of the coil.

Magnetic field B₂ when the wire is at a distance, 2d from the center of the coil


Change in the magnetic field, ΔB = B₂ - B₁ = 0.00001725 - 0.0000345
ΔB = -0.000001725
Induced current, 
E = -N (Δ∅)/Δt
Δ∅ = A ΔB
Area, A = πr²
diameter, d = 0.0125 m
Radius, r = 0.00625 m
A = π* 0.00625²
A = 0.0001227 m²
Δ∅ = -0.000001725 * 0.0001227
Δ∅ = -211.6575 * 10⁻¹²
E = -N (Δ∅)/Δt

Resistance, R = 3.25 μ ohms = 3.25 * 10⁻⁶ ohms
I = E/R

I = 0.0000693 A
I = 69 .3 * 10⁻⁶A
I = 69.3 μA
Answer: Option (b) is the correct answer.
Explanation:
As Kristina is over training, therefore, there is pain in her muscles because human body also requires rest in order to work or function properly.
That is why, gym trainers suggest to give one day off in a week for your workout sessions so that body muscles should recover.
Thus, we can conclude that if Kristina is over training, then recovery training principle should Kristina consider before continuing her program.
<span>We put a motion detector at </span>one end of the track<span> and put a cart on the track. ... Next, we put a motorized fan on the cart and let it push the cart down the track. ... This is what I would expect based on the velocity graph, since </span>acceleration<span> equals the slope of the velocity graph, which remains</span>constant<span> in time.</span>