Net flux through the cylindrical surface is given as

here q = enclosed charge in the surface
so here in order to find the value of q

so now we have

so this is the total flux
now by Gauss's law we can find the electric field




<em>by above expression we can find the electric field at required position</em>
Answer:
a) Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2 = 239.6 N,
b) Ha = 1863.75 N, nfs = 1 , length = 11.8 mm
Explanation:
Given that:
γ= 9.5 kN/m³ = 9500N/m3
b = 6 inches = 0.1524 m
t = 0.0013 mm
d = 2 inches = 0.0508 m
n = 1750 rpm

L = 9 ft = 2.7432 m
Ks = 1.25
g = 9.81 m/s²
a)







b)


dip = 
Answer:
P = ρRT/M
Explanation:
Ideal gas equation is given as follows generally:
PV = nRT (1)
P = pressure in the containing vessel
V = volume of the containing vessel
n = number of moles
R = gas constant
T = temperature in K
n = m/M
m = mass of the gas contained in the vessel in g
M = molar mass in g/mol
ρ = m/V
Density of the gas = ρ
Substituting for n in (1)
PV = mRT/M. (2)
Dividing equation (2) through by V
P = m/V ×RT/M
P = ρRT/M
Answer:
We can conclude that there is a decrease in kinetic energy of the particles due to their elastic collision, since kinetic energy is directly proportional to squared velocity of the particles.
Explanation:
Given:
initial velocity of particle A, Ua = 5m/s
initial velocity of particle B, Ub = 10 m/s
final velocity of particle A, Va = 4m/s
final velocity of particle B, Vb = 7m/s
For particle A:
The final velocity is 1 less than the initial velocity.
For particle B:
The final velocity is 3 less than the initial velocity.
We can conclude that there is a loss in kinetic energy due to elastic collision of the two particles, since kinetic energy is directly proportional to squared velocity of the particles. A decrease in velocity means decrease in kinetic energy.